Showing posts with label July 2024 Question Paper. Show all posts
Showing posts with label July 2024 Question Paper. Show all posts

10th Maths Algebra Question Paper with Solutions July 2024 (Hindi Medium)

SSC рдЗрдпрдд्рддा резреж рд╡ीं рдмीрдЬрдЧрдгिрдд рдк्рд░рд╢्рдирдкрдд्рд░िрдХा рд╣рд▓ - рдЬुрд▓ाрдИ реирежреирек (рд╣िंрджी рдоाрдз्рдпрдо)

рдк्рд░рд╢्рди рез. (A) рдиिрдо्рдирд▓िрдЦिрдд рдк्рд░рдд्рдпेрдХ рдЙрдкрдк्рд░рд╢्рди рдХे рд▓िрдП рдЪाрд░ рд╡िрдХрд▓्рдк рджिрдпे рд╣ैं। рдЙрдирдоें рд╕े рд╕рд╣ी рд╡िрдХрд▓्рдк рдЪुрдирдХрд░ рдЙрд╕рдХा рд╡рд░्рдгाрдХ्рд╖рд░ рд▓िрдЦिрдП : (рек рдЕंрдХ)
(i) x рддрдеा y рдЪрд░ांрдХ рд╡ाрд▓े рдпुрдЧрдкрдд рд╕рдоीрдХрд░рдг рдХे рд▓िрдП рдпрджि $D_{x}=49$, $D_{y}=-63$ рддрдеा $D=7$ рд╣ो, рддो $x=$ рдХिрддрдиा ?
рд╡िрдХрд▓्рдк: (A) 7, (B) -7, (C) 1/7, (D) -1/7
рд╣рд▓:
рдХ्рд░ेрдорд░ рдкрдж्рдзрддि рдХे рдЕрдиुрд╕ाрд░, $x = \frac{D_x}{D}$
$x = \frac{49}{7} = 7$
[cite_start]рдЙрдд्рддрд░: (A) [cite: 497]
(ii) рдиिрдо्рдирд▓िрдЦिрдд рдоें рд╕े рдХौрдирд╕ा рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рд╣ै ?
рд╡िрдХрд▓्рдк:
(A) $\frac{5}{x}-3=x^{2}$ (рдпрд╣ рдШрди рд╕рдоीрдХрд░рдг рд╣ोрдЧा)
(B) $x(x+5)=2$ ($x^2+5x-2=0$, рдХोрдЯि реи рд╣ै)
(C) $n-1=2n$ (рд░ेрдЦीрдп рд╕рдоीрдХрд░рдг)
(D) $\frac{1}{x^{2}}(x+2)=x$ (рдпрд╣ рдШрди рд╕рдоीрдХрд░рдг рд╣ोрдЧा)
[cite_start]рдЙрдд्рддрд░: (B) [cite: 510]
(iii) -10, -6, -2, 2, ... рдпрд╣ рд╢्рд░ृंрдЦрд▓ा ........
рд╡िрдХрд▓्рдк:
(A) рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рд╣ै рдХ्рдпोंрдХि $d=-16$
(B) рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рд╣ै рдХ्рдпोंрдХि $d=4$
(C) рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рд╣ै рдХ्рдпोंрдХि $d=-4$
(D) рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рдирд╣ीं рд╣ै
рд╣рд▓: $d = t_2 - t_1 = -6 - (-10) = -6 + 10 = 4$.
[cite_start]рдЙрдд्рддрд░: (B) [cite: 521]
(iv) рдиिрдо्рдирд▓िрдЦिрдд рдоें рд╕े рдХौрдирд╕ी рд╕ंрднाрд╡्рдпрддा рд╣ो рдирд╣ीं рд╕рдХрддी ?
рд╡िрдХрд▓्рдк: (A) 2/3, (B) 1.5, (C) 15%, (D) 0.7
рд╣рд▓: рд╕ंрднाрд╡्рдпрддा 0 рд╕े 1 рдХे рдмीрдЪ рд╣ोрддी рд╣ै। 1.5 рдпрд╣ рд╕ंрдЦ्рдпा 1 рд╕े рдмреЬी рд╣ै।
[cite_start]рдЙрдд्рддрд░: (B) [cite: 530]
рдк्рд░рд╢्рди рез. (B) рдиिрдо्рдирд▓िрдЦिрдд рдЙрдкрдк्рд░рд╢्рди рд╣рд▓ рдХीрдЬिрдП : (рек рдЕंрдХ)
(i) рдиिрдо्рди рдиिрд╢्рдЪрдпрдХ рдХा рдоाрди рдЬ्рдЮाрдд рдХीрдЬिрдП : $\begin{vmatrix}5 & -2 \\ -3 & 1\end{vmatrix}$
рдоाрди = $(5 \times 1) - (-2 \times -3)$
$= 5 - (6)$
$= 5 - 6 = -1$
[cite_start]рдоाрди = -1 [cite: 539]
(ii) рдиिрдо्рди рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ृंрдЦрд▓ा рдХा рдк्рд░рдердо рдкрдж рддрдеा рд╕ाрдоाрди्рдп рдЕंрддрд░ рдЬ्рдЮाрдд рдХीрдЬिрдП : 5, 1, -3, -7...
рдк्рд░рдердо рдкрдж ($a$) = 5
рд╕ाрдоाрди्рдп рдЕंрддрд░ ($d$) = $t_2 - t_1 = 1 - 5 = -4$
[cite_start]a = 5, d = -4 [cite: 541]
(iii) рдпрджि рд╢ेрдпрд░ рдХा рдЕंрдХिрдд рдоूрд▓्рдп = 100 рд░ुрдкрдпे; рдЕрдзिрдоूрд▓्рдп = 65 рд░ुрдкрдпे рд╣ो, рддो рдЙрд╕ рд╢ेрдпрд░ рдХा рдмाрдЬाрд░ рдоूрд▓्рдп рдЬ्рдЮाрдд рдХीрдЬिрдП।
рдмाрдЬाрд░ рдоूрд▓्рдп (MV) = рдЕंрдХिрдд рдоूрд▓्рдп + рдЕрдзिрдоूрд▓्рдп
MV = $100 + 65 = 165$
[cite_start]рдмाрдЬाрд░ рдоूрд▓्рдп = 165 рд░ुрдкрдпे [cite: 545]
(iv) рдПрдХ рдкाँрд╕ा рдлेंрдХрдиे рдкрд░ рдирдоूрдиा рдЕрд╡рдХाрд╢ рд▓िрдЦिрдпे।
рдирдоूрдиा рдЕрд╡рдХाрд╢ $S = \{1, 2, 3, 4, 5, 6\}$
[cite_start]S = {1, 2, 3, 4, 5, 6} [cite: 549]

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рдк्рд░рд╢्рди реи. (A) рдиिрдо्рдирд▓िрдЦिрдд рдХोрдИ рджो рдХृрддि рдкूрд░्рдг рдХीрдЬिрдпे : (рек рдЕंрдХ)
(i) рджिрдпे рдЧрдпे рд╕рдоीрдХрд░рдг рдХा рдЖрд▓ेрдЦ рдЦींрдЪрдиे рдХे рд▓िрдП рдиिрдо्рди рд╕ाрд░рдгी рдкूрд░्рдг рдХीрдЬिрдпे : $x+2y=4$
x -2 0 2
y 3 2 1
(x, y) (-2, 3) (0, 2) (2, 1)
рд╕्рдкрд╖्рдЯीрдХрд░рдг: рдпрджि x=-2, -2+2y=4 → 2y=6 → y=3. [cite_start]рдпрджि y=1, x+2(1)=4 → x=2. [cite: 554]
(ii) рд╡िрд╡ेрдЪрдХ рдХे рдоाрди рд╕े рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рдХे рдоूрд▓ рдХो рдиिрд╢्рдЪिрдд рдХीрдЬिрдП : $m^{2}+2m+9=0$
рддुрд▓рдиा рдХрд░рдиे рдкрд░:
$a = 1, b=2, c=9$
$b^{2}-4ac = 2^{2} - 4 \times 1 \times \boxed{9}$
$= 4 - 36$
$b^{2}-4ac = \boxed{-32}$
$b^{2}-4ac < 0$
[cite_start]рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рдХे рдоूрд▓ рд╡ाрд╕्рддрд╡िрдХ рд╕ंрдЦ्рдпा рдирд╣ीं рд╣ैं। [cite: 559]
(iii) рд╕्рдоिрддा рдиे 12,000 рд░ुрдкрдпे рдиिрд╡ेрд╢ рдХрд░ 10 рд░ुрдкрдпे рдЕंрдХिрдд рдоूрд▓्рдп рд╡ाрд▓े рд╢ेрдпрд░्рд╕ рдк्рд░рддि рд╢ेрдпрд░ 2 рд░ुрдкрдпे рдЕрдзिрдоूрд▓्рдп рдкрд░ рдЦрд░ीрджे, рддो рдЙрд╕े рдХुрд▓ рдХिрддрдиे рд╢ेрдпрд░्рд╕ рдк्рд░ाрдк्рдд рд╣ोंрдЧे। рдпрд╣ рдЬ्рдЮाрдд рдХрд░рдиे рдХे рд▓िрдП рдиिрдо्рди рдХृрддि рдкूрд░ी рдХीрдЬिрдП।
$FV=10$, рдЕрдзिрдоूрд▓्рдп = 2 рд░ुрдкрдпे
рдмाрдЬाрд░ рдоूрд▓्рдп = рдЕंрдХिрдд рдоूрд▓्рдп + рдЕрдзिрдоूрд▓्рдп = 10 + 2 = 12 рд░ुрдкрдпे
рд╢ेрдпрд░्рд╕ рдХी рд╕ंрдЦ्рдпा = $\frac{\text{рдХुрд▓ рдиिрд╡ेрд╢}}{\text{рдмाрдЬाрд░ рдоूрд▓्рдп}}$
$= \frac{12,000}{\boxed{12}}$
[cite_start]$= \boxed{1000} \text{ рд╢ेрдпрд░्рд╕.}$ [cite: 572]
рдк्рд░рд╢्рди реи. (B) рдиिрдо्рдирд▓िрдЦिрдд рдХोрдИ рднी рдЪाрд░ рдЙрдкрдк्рд░рд╢्рди рд╣рд▓ рдХीрдЬिрдП : (рео рдЕंрдХ)
(i) рдиिрдо्рдирд▓िрдЦिрдд рдпुрдЧрдкрдд рд╕рдоीрдХрд░рдгों рдХो рд╣рд▓ рдХीрдЬिрдП : $x+y=5$, $x-y=3$
$x+y=5$ ... (I)
$x-y=3$ ... (II)
рд╕рдоीрдХрд░рдг (I) рдФрд░ (II) рдЬोреЬрдиे рдкрд░:
$2x = 8 \Rightarrow x = 4$
x рдХा рдоाрди рд╕рдоीрдХрд░рдг (I) рдоें рд░рдЦрдиे рдкрд░:
$4 + y = 5 \Rightarrow y = 1$
[cite_start]рд╣рд▓: (x, y) = (4, 1) [cite: 590]
(ii) рдпрджि $x=3$ рдпрд╣ $kx^{2}-10x+3=0$ рд╕рдоीрдХрд░рдг рдХा рдПрдХ рдоूрд▓ рд╣ै, рддो k рдХा рдоाрди рдЬ्рдЮाрдд рдХीрдЬिрдП।
рд╕рдоीрдХрд░рдг рдоें $x=3$ рд░рдЦрдиे рдкрд░:
$k(3)^2 - 10(3) + 3 = 0$
$9k - 30 + 3 = 0$
$9k - 27 = 0$
$9k = 27 \Rightarrow k = 3$
[cite_start]k = 3 [cite: 591]
(iii) рджी рд╣ुрдИ рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ृंрдЦрд▓ा рдХा 19рд╡ाँ рдкрдж рдЬ्рдЮाрдд рдХीрдЬिрдпे : 7, 13, 19, 25...
$a = 7, d = 13 - 7 = 6, n = 19$
рд╕ूрдд्рд░: $t_n = a + (n-1)d$
$t_{19} = 7 + (19-1)6$
$t_{19} = 7 + (18 \times 6)$
$t_{19} = 7 + 108 = 115$
[cite_start]19рд╡ाँ рдкрдж 115 рд╣ै। [cite: 596]
(iv) рдХिрд╕ी рд░िрд╕्рдЯ рд╡ॉрдЪ рдмेрд▓्рдЯ рдХा рдХрд░рдкाрдд्рд░ рдоूрд▓्рдп 586 рд░ुрдкрдпे рд╣ै। GST рдХी рджрд░ рдпрджि 18% рд╣ो, рддो рдмेрд▓्рдЯ рдЧ्рд░ाрд╣рдХ рдХो рдХिрддрдиे рд░ुрдкрдпों рдоें рдк्рд░ाрдк्рдд рд╣ोрдЧी ?
рдХрд░рдкाрдд्рд░ рдоूрд▓्рдп = 586 рд░ुрдкрдпे
GST рд░ाрд╢ि = $586 \times \frac{18}{100} = 586 \times 0.18 = 105.48$
рдХुрд▓ рдоूрд▓्рдп = рдХрд░рдкाрдд्рд░ рдоूрд▓्рдп + GST
рдХुрд▓ рдоूрд▓्рдп = $586 + 105.48 = 691.48$
[cite_start]рдЧ्рд░ाрд╣рдХ рдХे рд▓िрдП рдоूрд▓्рдп = 691.48 рд░ुрдкрдпे [cite: 597]
(v) рдХिрд╕ी рдкрд░िрд╡ाрд░ рдоें рд╡ाрд░्рд╖िрдХ рдиिрд╡ेрд╢ рдХा рд╡ृрдд्рддाрд▓ेрдЦ рджिрдпा рдЧрдпा рд╣ै। рд╢ेрдпрд░्рд╕: $60^\circ$, рд╕्рдеाрдиीрдп рдоाрд▓рдордд्рддा: $120^\circ$, рдо्рдпुрдЪ्рдпुрдЕрд▓ рдлंрдб: $60^\circ$, рдмैंрдХ рдоें рд╕ीрдзी рдЬрдоा: $90^\circ$, рдбाрдХрдШрд░: $30^\circ$. рдпрджि рд╢ेрдпрд░्рд╕ рдоें рдиिрд╡ेрд╢ рд░ाрд╢ि 2,000 рд╣ो, рддो рдХुрд▓ рдиिрд╡ेрд╢ рдФрд░ рдбाрдХрдШрд░ рдоें рдиिрд╡ेрд╢ рдЬ्рдЮाрдд рдХीрдЬिрдпे।
(a) рд╢ेрдпрд░्рд╕ рдХे рд▓िрдП рдХेंрдж्рд░ीрдп рдХोрдг = $\frac{\text{рд╢ेрдпрд░्рд╕ рдоें рдиिрд╡ेрд╢}}{\text{рдХुрд▓ рдиिрд╡ेрд╢}} \times 360^\circ$
$60^\circ = \frac{2000}{\text{рдХुрд▓}} \times 360^\circ$
$\text{рдХुрд▓ рдиिрд╡ेрд╢} = \frac{2000 \times 360}{60} = 2000 \times 6 = 12,000$

(b) рдбाрдХрдШрд░ рдоें рдиिрд╡ेрд╢:
рдбाрдХрдШрд░ рдХा рдХोрдг = $30^\circ$
$\text{рд░ाрд╢ि} = \frac{30}{360} \times 12,000 = \frac{1}{12} \times 12,000 = 1,000$
рдХुрд▓ рдиिрд╡ेрд╢ = 12,000 рд░ुрдкрдпे; [cite_start]рдбाрдХрдШрд░ рдоें рдиिрд╡ेрд╢ = 1,000 рд░ुрдкрдпे [cite: 614]
рдк्рд░рд╢्рди рей. (A) рдиिрдо्рдирд▓िрдЦिрдд рдХोрдИ рднी рдПрдХ рдХृрддि рдкूрд░ी рдХीрдЬिрдпे : (рей рдЕंрдХ)
(i) рдХिрд╕ी рдПрдХ рд╢ेрдпрд░ рдХा рдмाрдЬाрд░ рдоूрд▓्рдп 1,000 рд░ुрдкрдпे рд╣ै। рдЙрд╕ рд╢ेрдпрд░ рдХो рдмेрдЪрдиे рдкрд░ рдЙрд╕ рдкрд░ 0.1% рджрд▓ाрд▓ी рджी, рддो рдмेрдЪрдиे рдХे рдмाрдж рдоिрд▓рдиे рд╡ाрд▓ी рд░рдХрдо рдХिрддрдиी рд╣ै ?
рджрд▓ाрд▓ी рд░рдХрдо = рдмाрдЬाрд░ рдоूрд▓्рдп $\times$ рджрд▓ाрд▓ी рдХी рджрд░
$= 1000 \times \frac{0.1}{\boxed{100}}$
$= 10 \times 0.1 = \boxed{1}$
рд╢ेрдпрд░ рдмेрдЪрдиे рдкрд░ рдоिрд▓рдиे рд╡ाрд▓ी рд░рдХрдо = рдмाрдЬाрд░ рдоूрд▓्рдп - рджрд▓ाрд▓ी
$= 1000 - \boxed{1}$
[cite_start]$= \boxed{999} \text{ рд░ुрдкрдпे.}$ [cite: 625]
(ii) рдПрдХ рдкाँрд╕े рдХे рдКрдкрд░ी рдкृрд╖्рдарднाрдЧ рдкрд░ 2, 4, 6, 8, 10, 12 рд╕ंрдЦ्рдпाрдПँ рд╣ैं। рдпрд╣ рдкाँрд╕ा рдПрдХ рдмाрд░ рдЙрдЫाрд▓рдиे рдкрд░ рдКрдкрд░ी рдкृрд╖्рдарднाрдЧ рдкрд░ рдоिрд▓рдиे рд╡ाрд▓ी рд╕ंрдЦ्рдпा рдкूрд░्рдг рд╡рд░्рдЧ рд╣ो рдпрд╣ рд╕ंрднाрд╡्рдпрддा рдоिрд▓рдиे рдХी рдХृрддि рдкूрд░्рдг рдХीрдЬिрдП।
$S = \{2, 4, 6, 8, 10, 12\}$
$n(S) = \boxed{6}$
рдШрдЯрдиा B: рд╕ंрдЦ्рдпा рдкूрд░्рдг рд╡рд░्рдЧ рд╣ोрдиा। рдХेрд╡рд▓ 4 рдпрд╣ рдкूрд░्рдг рд╡рд░्рдЧ рд╕ंрдЦ्рдпा рд╣ै ($2^2$).
$B = \{ \boxed{4} \}$
$n(B) = \boxed{1}$
[cite_start]$P(B) = \frac{n(B)}{n(S)} = \frac{\boxed{1}}{6}$ [cite: 638]
рдк्рд░рд╢्рди рей. (B) рдиिрдо्рдирд▓िрдЦिрдд рдХोрдИ рджो рдЙрдкрдк्рд░рд╢्рди рд╣рд▓ рдХीрдЬिрдпे : (рем рдЕंрдХ)
(i) рдиिрдо्рдирд▓िрдЦिрдд рдпुрдЧрдкрдд рд╕рдоीрдХрд░рдг рдХ्рд░ेрдорд░ рдкрдж्рдзрддि рд╕े рд╣рд▓ рдХीрдЬिрдП : $4m-2n=-4; 4m+3n=16$.
$D = \begin{vmatrix}4 & -2 \\ 4 & 3\end{vmatrix} = (12) - (-8) = 20$
$D_m = \begin{vmatrix}-4 & -2 \\ 16 & 3\end{vmatrix} = (-12) - (-32) = 20$
$D_n = \begin{vmatrix}4 & -4 \\ 4 & 16\end{vmatrix} = (64) - (-16) = 80$
$m = \frac{D_m}{D} = \frac{20}{20} = 1$
$n = \frac{D_n}{D} = \frac{80}{20} = 4$
[cite_start]рд╣рд▓: (m, n) = (1, 4) [cite: 651]
(ii) рдиिрдо्рдирд▓िрдЦिрдд рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рд╕ूрдд्рд░ рдкрдж्рдзрддि рд╕े рд╣рд▓ рдХीрдЬिрдП : $y^{2}+\frac{1}{3}y=2$
3 рд╕े рдЧुрдгा рдХрд░рдиे рдкрд░: $3y^2 + y = 6 \Rightarrow 3y^2 + y - 6 = 0$
$a=3, b=1, c=-6$
$b^2 - 4ac = (1)^2 - 4(3)(-6) = 1 + 72 = 73$
$y = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$
$y = \frac{-1 \pm \sqrt{73}}{6}$
[cite_start]рдоूрд▓: $\frac{-1+\sqrt{73}}{6}, \frac{-1-\sqrt{73}}{6}$ [cite: 657]
(iii) рджो рдкाँрд╕े рдЙрдЫाрд▓рдиे рдкрд░ рдирдоूрдиा рдЕрд╡рдХाрд╢ 'S' рддрдеा $n(S)$ рд▓िрдЦो рддрдеा рдШрдЯрдиा A рдФрд░ B рд▓िрдЦिрдП।
$S = \{(1,1)...(6,6)\}$, $n(S) = 36$.
рдШрдЯрдиा A: рд╕ंрдЦ्рдпाрдУं рдХा рдпोрдЧрдлрд▓ 5 рдХा рдЧुрдгрдЬ рд╣ै।
рдпोрдЧрдлрд▓ 5 рдпा 10 рд╣ो рд╕рдХрддा рд╣ै।
$A = \{(1,4), (2,3), (3,2), (4,1), (4,6), (5,5), (6,4)\}$
$n(A) = 7$

рдШрдЯрдиा B: рд╕ंрдЦ्рдпाрдУं рдХा рдпोрдЧрдлрд▓ 25 рд╣ै।
рдЕрдзिрдХрддрдо рдпोрдЧрдлрд▓ 12 (6+6) рд╣ोрддा рд╣ै। рдпोрдЧрдлрд▓ 25 рдЕрд╕ंрднрд╡ рд╣ै।
$B = \{ \}$ (рд░िрдХ्рдд рд╕рдоुрдЪ्рдЪрдп)
[cite_start]$n(B) = 0$ [cite: 658]
рдк्рд░рд╢्рди рек. рдиिрдо्рдирд▓िрдЦिрдд рдХोрдИ рднी рджो рдЙрдкрдк्рд░рд╢्рди рд╣рд▓ рдХीрдЬिрдП : (рео рдЕंрдХ)
(i) рдЯोрд▓ рдиाрдХे рдкрд░ рдЬрдоा рдХрд░ (рд░ुрдкрдпों рдоें) рд╡ рд╡ाрд╣рдиों рдХी рд╕ंрдЦ्рдпा рджी рдЧрдИ рд╣ै। рдЬрдоा рдХिрдП рдЧрдП рдХрд░ рдХा рдоाрдз्рдп "рдЕрдиुрдоाрдиिрдд рдоाрдз्рдп" рдкрдж्рдзрддि рд╕े рдЬ्рдЮाрдд рдХीрдЬिрдП।
рдЕрдиुрдоाрдиिрдд рдоाрдз्рдп $A = 550$ рдоाрдиेंрдЧे (500-600 рдХा рд╡рд░्рдЧрдордз्рдп)।
рд╡рд░्рдЧ (рдХрд░) рд╡рд░्рдЧрдордз्рдп ($x_i$) $d_i = x_i - 550$ рдмाрд░ंрдмाрд░рддा ($f_i$) $f_i d_i$
300-400350-20080-16000
400-500450-100110-11000
500-60055001200
600-700650100707000
700-800750200408000
рдХुрд▓ $\sum f_i = 420$ $\sum f_i d_i = -12000$
$\bar{d} = \frac{\sum f_i d_i}{\sum f_i} = \frac{-12000}{420} \approx -28.57$
рдоाрдз्рдп $\bar{X} = A + \bar{d} = 550 + (-28.57) = 521.43$
[cite_start]рдФрд╕рдд рдХрд░ = 521.43 рд░ुрдкрдпे [cite: 664]
(ii) рдордиीрд╖ा рдХो 540 рдХेрд▓े рдХुрдЫ рдЫाрдд्рд░ों рдоें рд╕рдоाрди рд░ूрдк рд╕े рдмाँрдЯрдиे рд╣ैं। рдпрджि 30 рдЫाрдд्рд░ рдЕрдзिрдХ рд╣ोрддे рддो рдк्рд░рдд्рдпेрдХ рдЫाрдд्рд░ рдХो 3 рдХेрд▓े рдХрдо рдоिрд▓рддे рддो рдЫाрдд्рд░ों рдХी рд╕ंрдЦ्рдпा рдЬ्рдЮाрдд рдХीрдЬिрдП।
рдоाрдиा рдЫाрдд्рд░ों рдХी рдоूрд▓ рд╕ंрдЦ्рдпा = $x$. рдк्рд░рдд्рдпेрдХ рдХो рдоिрд▓рдиे рд╡ाрд▓े рдХेрд▓े = $540/x$.
рдирдИ рдЫाрдд्рд░ рд╕ंрдЦ्рдпा = $x+30$. рдирдП рдХेрд▓े рдк्рд░рддि рдЫाрдд्рд░ = $540/(x+30)$.
рд╢рд░्рдд: рдкुрд░ाрдиा рд╣िрд╕्рд╕ा - рдирдпा рд╣िрд╕्рд╕ा = 3
$\frac{540}{x} - \frac{540}{x+30} = 3$
3 рд╕े рднाрдЧ рджेрдиे рдкрд░: $\frac{180}{x} - \frac{180}{x+30} = 1$
$180(x+30) - 180x = x(x+30)$
$180x + 5400 - 180x = x^2 + 30x$
$x^2 + 30x - 5400 = 0$
5400 рдХे рдЧुрдгрдирдЦंрдб рдЬिрдирдХा рдЕंрддрд░ 30 рд╣ै: 90 рдФрд░ 60.
$(x+90)(x-60) = 0$
$x = 60$ (рдЫाрдд्рд░ рд╕ंрдЦ्рдпा рдЛрдгाрдд्рдордХ рдирд╣ीं рд╣ो рд╕рдХрддी)।
[cite_start]рдЫाрдд्рд░ों рдХी рд╕ंрдЦ्рдпा = 60 [cite: 671]
(iii) 2,000 рд░ुрдкрдпे рдХा 10% рд╕ाрдзाрд░рдг рдм्рдпाрдЬ рдХी рджрд░ рд╕े рдиिрд╡ेрд╢ рдХिрдпा рддो рдк्рд░рдд्рдпेрдХ рд╡рд░्рд╖ рдХे рдЕंрдд рдоें рдоिрд▓рдиे рд╡ाрд▓ी рдм्рдпाрдЬ рдХी рд░рдХрдо рдХ्рдпा рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ृंрдЦрд▓ा рд╣ोрдЧी ? 10 рд╡рд░्рд╖ рдмाрдж рдк्рд░ाрдк्рдд рд╣ोрдиे рд╡ाрд▓ी рдм्рдпाрдЬ рдХी рд░рдХрдо рдЬ्рдЮाрдд рдХीрдЬिрдП।
рдоूрд▓рдзрди = 2000, рджрд░ = 10%.
рд╡рд░्рд╖ 1 рдХा рдм्рдпाрдЬ: $(2000 \times 10 \times 1)/100 = 200$
рд╡рд░्рд╖ 2 рдХा рдм्рдпाрдЬ: $(2000 \times 10 \times 2)/100 = 400$
рд╡рд░्рд╖ 3 рдХा рдм्рдпाрдЬ: 600...
рд╢्рд░ृंрдЦрд▓ा: 200, 400, 600...
рд╕ाрдоाрди्рдп рдЕंрддрд░ $d = 200$ рд╕्рдеिрд░ рд╣ै। рдЗрд╕рд▓िрдП рдпрд╣ рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рд╣ै।
10 рд╡рд░्рд╖ рдмाрдж рдХा рдм्рдпाрдЬ ($t_{10}$):
$t_{10} = a + 9d = 200 + 9(200) = 200 + 1800 = 2000$.
[cite_start]10 рд╡рд░्рд╖ рдмाрдж рдм्рдпाрдЬ = 2,000 рд░ुрдкрдпे [cite: 673]
(iv) [рд╕ांрдЦ्рдпिрдХी - рдмрд╣ुрд▓рдХ] рдмाрд░ंрдмाрд░рддा рд╕ाрд░рдгी рддैрдпाрд░ рдХीрдЬिрдП рдФрд░ рдмрд╣ुрд▓рдХ рдЬ्рдЮाрдд рдХीрдЬिрдП।
рджी рдЧрдИ рдЬाрдирдХाрд░ी: 0-20 (10%), 20-40 (20%), 40-60 (35%), 60-80 (20%), 80-100 (рдмрдЪे рд╣ुрдП 30 рдЫाрдд्рд░)।
рдХुрд▓ рдк्рд░рддिрд╢рдд = $10+20+35+20 = 85\%$. рдмрдЪे рд╣ुрдП = $15\%$.
рдпрджि $15\% = 30$ рдЫाрдд्рд░, рддो рдХुрд▓ рдЫाрдд्рд░ $N = (30/15) \times 100 = 200$.
рдмाрд░ंрдмाрд░рддा рд╕ाрд░рдгी:
0-20: $10\% \text{ of } 200 = 20$
20-40: $20\% \text{ of } 200 = 40$ ($f_0$)
40-60: $35\% \text{ of } 200 = 70$ ($f_1$ - рдмрд╣ुрд▓рдХीрдп рд╡рд░्рдЧ)
60-80: $20\% \text{ of } 200 = 40$ ($f_2$)
80-100: 30

рдмрд╣ुрд▓рдХ:
рдмрд╣ुрд▓рдХीрдп рд╡рд░्рдЧ: 40-60. $L=40, h=20, f_1=70, f_0=40, f_2=40$.
рдмрд╣ुрд▓рдХ $= L + [\frac{f_1-f_0}{2f_1-f_0-f_2}] \times h$
$= 40 + [\frac{70-40}{140-40-40}] \times 20$
$= 40 + [\frac{30}{60}] \times 20$
$= 40 + 10 = 50$
[cite_start]рдмрд╣ुрд▓рдХ = 50 рдЕंрдХ [cite: 678]
рдк्рд░рд╢्рди рел. рдиिрдо्рдирд▓िрдЦिрдд рдк्рд░рд╢्рдиों рдоें рд╕े рдХोрдИ рдПрдХ рдЙрдкрдк्рд░рд╢्рди рд╣рд▓ рдХीрдЬिрдпे : (рей рдЕंрдХ)
(i) рдиिрдо्рди рд╕ाрдордЧ्рд░ी рдЖрдпрддाрд▓ेрдЦ рдж्рд╡ाрд░ा рджрд░्рд╢ाрдУ :
рджी рдЧрдИ рдЬाрдирдХाрд░ी: 60-80 (4), 80-100 (12), 100-120 (16), 120-140 (8).
Draw histogram of the following data:Data given: 60-80 (4), 80-100 (12), 100-120 (16), 120-140 (8). рдиोрдЯ: рдЗрд╕рдХे рд▓िрдП рдЖрд▓ेрдЦ рдмрдиाрдиा рдЖрд╡рд╢्рдпрдХ рд╣ै। [cite_start]X-рдЕрдХ्рд╖ рдкрд░ 'рдмुрдж्рдзрдпांрдХ' рдФрд░ Y-рдЕрдХ्рд╖ рдкрд░ 'рдЫाрдд्рд░ рд╕ंрдЦ्рдпा' рд▓ेрдХрд░ рд╕рд▓рдЧ рд╕्рддंрдн рдмрдиाрдПँ। [cite: 689]
(ii) рдЖрдХृрддि рдоें рджी рдЧрдИ рдЬाрдирдХाрд░ी рдХे рдЖрдзाрд░ рд╕े рдЖрдпрдд рдХी рд▓ंрдмाрдИ рддрдеा рдЪौрдб़ाрдИ рд╕ेрдоी рдоें рдЬ्рдЮाрдд рдХीрдЬिрдП।
Find length and breadth of rectangle using given figure рдЖрдпрдд рдХी рд╕рдо्рдоुрдЦ рднुрдЬाрдПँ рд╕рдоाрди рд╣ोрддी рд╣ैं।
1) $2m + 3n + 5 = 5m + n$
$5m - 2m + n - 3n = 5$
$3m - 2n = 5$ ... (I)

2) $3m - 2n + 7 = m + n - 3$
$3m - m - 2n - n = -3 - 7$
$2m - 3n = -10$ ... (II)

рд╕рдоीрдХрд░рдг (I) рдХो 3 рд╕े рдФрд░ (II) рдХो 2 рд╕े рдЧुрдгा рдХрд░ें:
$9m - 6n = 15$
$4m - 6n = -20$
рдШрдЯाрдиे рдкрд░: $5m = 35 \Rightarrow m = 7$.

m=7 рд╕рдоीрдХрд░рдг (I) рдоें рд░рдЦрдиे рдкрд░:
$3(7) - 2n = 5$
$21 - 5 = 2n$
$16 = 2n \Rightarrow n = 8$.

рдЖрдпрдд рдХी рд╡िрдоाрдПँ:
рд▓ंрдмाрдИ $= 5m + n = 5(7) + 8 = 35 + 8 = 43$.
рдЪौрдб़ाрдИ $= m + n - 3 = 7 + 8 - 3 = 12$.
[cite_start]рд▓ंрдмाрдИ = 43 рд╕ेрдоी, рдЪौрдб़ाрдИ = 12 рд╕ेрдоी [cite: 692]
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10th Maths Algebra Question Paper with Solutions July 2024 (Marathi Medium)

SSC рдЗрдпрдд्рддा резреж рд╡ी рдмीрдЬрдЧрдгिрдд рдк्рд░рд╢्рдирдкрдд्рд░िрдХा - рдЬुрд▓ै реирежреирек (рдЙрдХрд▓)

рдк्рд░рд╢्рди рез. (A) рдкुрдвीрд▓ рдк्рд░рдд्рдпेрдХ рдЙрдкрдк्рд░рд╢्рдиाрд╕ाрдаी рдЪाрд░ рдкрд░्рдпाрдпी рдЙрдд्рддрд░े рджिрд▓ी рдЖрд╣ेрдд. рдд्рдпाрдкैрдХी рдЕрдЪूрдХ рдкрд░्рдпाрдп рдиिрд╡рдбूрди рдд्рдпाрдЪे рд╡рд░्рдгाрдХ्рд╖рд░ рд▓िрд╣ा : (рек рдЧुрдг)
(i) x рд╡ y рд╣ी рдЪрд▓े рдЕрд╕рд▓ेрд▓्рдпा рдПрдХрд╕ाрдордпिрдХ рд╕рдоीрдХрд░рдгाрд╕ाрдаी рдЬрд░ $D_{x}=49$, $D_{y}=-63$ рд╡ $D=7$ рдЕрд╕ेрд▓, рддрд░ x = рдХिрддी ?
рдкрд░्рдпाрдп: (A) 7, (B) -7, (C) 1/7, (D) -1/7
рдЙрдХрд▓:
рдХ्рд░ेрдорд░рдЪ्рдпा рдкрдж्рдзрддीрдиुрд╕ाрд░, $x = \frac{D_x}{D}$
$x = \frac{49}{7} = 7$
рдЙрдд्рддрд░: (A)
(ii) рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддे рд╕рдоीрдХрд░рдг рд╣े рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рдЖрд╣े ?
рдкрд░्рдпाрдп:
(A) $\frac{5}{x}-3=x^{2}$ (рд╣े рдШрди рд╕рдоीрдХрд░рдг рд╣ोрдИрд▓)
(B) $x(x+5)=2$ ($x^2+5x-2=0$, рдХोрдЯी реи рдЖрд╣े)
(C) $n-1=2n$ (рд░ेрд╖ीрдп рд╕рдоीрдХрд░рдг)
(D) $\frac{1}{x^{2}}(x+2)=x$ (рд╣े рдШрди рд╕рдоीрдХрд░рдг рд╣ोрдИрд▓)
рдЙрдд्рддрд░: (B)
(iii) -10, -6, -2, 2, ... рд╣ी рдХ्рд░рдоिрдХा ........
рдкрд░्рдпाрдп:
(A) рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвी рдЖрд╣े, рдХाрд░рдг $d=-16$
(B) рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвी рдЖрд╣े, рдХाрд░рдг $d=4$
(C) рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвी рдЖрд╣े, рдХाрд░рдг $d=-4$
(D) рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвी рдиाрд╣ी
рдЙрдХрд▓: $d = t_2 - t_1 = -6 - (-10) = -6 + 10 = 4$.
рдЙрдд्рддрд░: (B)
(iv) рдЦाрд▓ीрд▓ рдкрд░्рдпाрдпांрдкैрдХी рдХोрдгрддी рд╕ंрдЦ्рдпा рд╕ंрднाрд╡्рдпрддा рдЕрд╕ू рд╢рдХрдгाрд░ рдиाрд╣ी ?
рдкрд░्рдпाрдп: (A) 2/3, (B) 1.5, (C) 15%, (D) 0.7
рдЙрдХрд▓: рд╕ंрднाрд╡्рдпрддा 0 рддे 1 рдЪ्рдпा рджрд░рдо्рдпाрди рдЕрд╕рддे. 1.5 рд╣ी рд╕ंрдЦ्рдпा 1 рдкेрдХ्рд╖ा рдоोрдаी рдЖрд╣े.
рдЙрдд्рддрд░: (B)
рдк्рд░рд╢्рди рез. (B) рдЦाрд▓ीрд▓ рдЙрдкрдк्рд░рд╢्рди рд╕ोрдбрд╡ा : (рек рдЧुрдг)
(i) рдкुрдвीрд▓ рдиिрд╢्рдЪрдпрдХाрдЪी рдХिंрдордд рдХाрдвा : $\begin{vmatrix}5 & -2 \\ -3 & 1\end{vmatrix}$
рдХिंрдордд = $(5 \times 1) - (-2 \times -3)$
$= 5 - (6)$
$= 5 - 6 = -1$
рдХिंрдордд = -1
(ii) рдкुрдвीрд▓ рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвीрд╕ाрдаी рдкрд╣िрд▓े рдкрдж рдЖрдгि рд╕ाрдоाрди्рдп рдлрд░рдХ рдХाрдвा : 5, 1, -3, -7...
рдкрд╣िрд▓े рдкрдж ($a$) = 5
рд╕ाрдоाрди्рдп рдлрд░рдХ ($d$) = $t_2 - t_1 = 1 - 5 = -4$
a = 5, d = -4
(iii) рдПрдХा рд╢ेрдЕрд░рдЪी рджрд░्рд╢рдиी рдХिंрдордд = 100 рд░ुрдкрдпे; рдЕрдзिрдоूрд▓्рдп = 65 рд░ुрдкрдпे рдЖрд╣े, рддрд░ рдд्рдпा рд╢ेрдЕрд░рдЪा рдмाрдЬाрд░рднाрд╡ рдХाрдвा.
рдмाрдЬाрд░рднाрд╡ (MV) = рджрд░्рд╢рдиी рдХिंрдордд + рдЕрдзिрдоूрд▓्рдп
MV = $100 + 65 = 165$
рдмाрдЬाрд░рднाрд╡ = 165 рд░ुрдкрдпे
(iv) рдПрдХ рдлाрд╕ा рдЯाрдХрд▓ा рдЕрд╕рддा рдирдоुрдиा рдЕрд╡рдХाрд╢ рд▓िрд╣ा.
рдирдоुрдиा рдЕрд╡рдХाрд╢ $S = \{1, 2, 3, 4, 5, 6\}$
S = {1, 2, 3, 4, 5, 6}

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рдк्рд░рд╢्рди реи. (A) рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрдд्рдпाрд╣ी рджोрди рдХृрддी рдкूрд░्рдг рдХрд░ूрди рд▓िрд╣ा : (рек рдЧुрдг)
(i) рджिрд▓ेрд▓्рдпा рд╕рдоीрдХрд░рдгाрдЪा рдЖрд▓ेрдЦ рдХाрдврдг्рдпाрд╕ाрдаी рдЦाрд▓ीрд▓ рд╕ाрд░рдгी рдкूрд░्рдг рдХрд░ा : $x+2y=4$
x -2 0 2
y 3 2 1
(x, y) (-2, 3) (0, 2) (2, 1)
рд╕्рдкрд╖्рдЯीрдХрд░рдг: рдЬрд░ x=-2, -2+2y=4 → 2y=6 → y=3. рдЬрд░ y=1, x+2(1)=4 → x=2.
(ii) рд╡िрд╡ेрдЪрдХाрдЪ्рдпा рдХिंрдорддीрд╡рд░ूрди рдЦाрд▓ीрд▓ рд╡рд░्рдЧрд╕рдоीрдХрд░рдгाрдЪ्рдпा рдоुрд│ांрдЪे рд╕्рд╡рд░ूрдк рдард░рд╡ा : $m^{2}+2m+9=0$
рддुрд▓рдиा рдХрд░ूрди:
$a = 1, b=2, c=9$
$b^{2}-4ac = 2^{2} - 4 \times 1 \times \boxed{9}$
$= 4 - 36$
$b^{2}-4ac = \boxed{-32}$
$b^{2}-4ac < 0$
рд╡рд░्рдЧрд╕рдоीрдХрд░рдгाрдЪी рдоुрд│े рд╡ाрд╕्рддрд╡ рд╕ंрдЦ्рдпा рдиाрд╣ीрдд.
(iii) рд╕्рдоिрддाрдиे 12,000 рд░ुрдкрдпे рдЧुंрддрд╡ूрди 10 рд░ुрдкрдпे рджрд░्рд╢рдиी рдХिंрдорддीрдЪे рд╢ेрдЕрд░्рд╕ 2 рд░ुрдкрдпे рдЕрдзिрдоूрд▓्рдпाрдиे рдШेрддрд▓े, рддрд░ рддिрд▓ा рдХिрддी рд╢ेрдЕрд░्рд╕ рдоिрд│рддीрд▓ рд╣े рдХाрдврдг्рдпाрд╕ाрдаी рдЦाрд▓ीрд▓ рдХृрддी рдкूрд░्рдг рдХрд░ा.
$FV=10$, рдЕрдзिрдоूрд▓्рдп = 2 рд░ुрдкрдпे
рдмाрдЬाрд░рднाрд╡ = рджрд░्рд╢рдиी рдХिंрдордд + рдЕрдзिрдоूрд▓्рдп = 10 + 2 = 12 рд░ुрдкрдпे
рд╢ेрдЕрд░्рд╕рдЪी рд╕ंрдЦ्рдпा = $\frac{\text{рдПрдХूрдг рдЧुंрддрд╡рдгूрдХ}}{\text{рдмाрдЬाрд░рднाрд╡}}$
$= \frac{12,000}{\boxed{12}}$
$= \boxed{1000} \text{ рд╢ेрдЕрд░्рд╕.}$
рдк्рд░рд╢्рди реи. (B) рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддेрд╣ी рдЪाрд░ рдЙрдкрдк्рд░рд╢्рди рд╕ोрдбрд╡ा : (рео рдЧुрдг)
(i) рдЦाрд▓ीрд▓ рдПрдХрд╕ाрдордпिрдХ рд╕рдоीрдХрд░рдгे рд╕ोрдбрд╡ा : $x+y=5$, $x-y=3$
$x+y=5$ ... (I)
$x-y=3$ ... (II)
рд╕рдоीрдХрд░рдг (I) рд╡ (II) рдЪी рдмेрд░ीрдЬ рдХрд░ू:
$2x = 8 \Rightarrow x = 4$
x рдЪी рдХिंрдордд рд╕рдоीрдХрд░рдг (I) рдордз्рдпे рдаेрд╡ूрди:
$4 + y = 5 \Rightarrow y = 1$
рдЙрдХрд▓: (x, y) = (4, 1)
(ii) рдЬрд░ $x=3$ рд╣े $kx^{2}-10x+3=0$ рдпा рд╕рдоीрдХрд░рдгाрдЪे рдПрдХ рдоूрд│ рдЕрд╕ेрд▓, рддрд░ k рдЪी рдХिंрдордд рдХाрдвा.
рд╕рдоीрдХрд░рдгाрдд $x=3$ рдаेрд╡ू:
$k(3)^2 - 10(3) + 3 = 0$
$9k - 30 + 3 = 0$
$9k - 27 = 0$
$9k = 27 \Rightarrow k = 3$
k = 3
(iii) рдЦाрд▓ीрд▓ рдЕंрдХрдЧрдгिрддी рд╢्рд░ेрдвीрдЪे 19 рд╡े рдкрдж рдХाрдвा : 7, 13, 19, 25...
$a = 7, d = 13 - 7 = 6, n = 19$
рд╕ूрдд्рд░: $t_n = a + (n-1)d$
$t_{19} = 7 + (19-1)6$
$t_{19} = 7 + (18 \times 6)$
$t_{19} = 7 + 108 = 115$
19 рд╡े рдкрдж 115 рдЖрд╣े.
(iv) рдПрдХा рд░िрд╕्рдЯрд╡ॉрдЪ рдмेрд▓्рдЯрдЪी рдХрд░рдкाрдд्рд░ рдХिंрдордд 586 рд░ुрдкрдпे рдЖрд╣े. GST рдЪा рджрд░ 18% рдЖрд╣े, рддрд░ рдЧ्рд░ाрд╣рдХाрд▓ा рддो рдмेрд▓्рдЯ рдХिрддी рд░ुрдкрдпाрд╕ рдоिрд│ेрд▓ ?
рдХрд░рдкाрдд्рд░ рдХिंрдордд = 586 рд░ुрдкрдпे
GST рд░рдХ्рдХрдо = $586 \times \frac{18}{100} = 586 \times 0.18 = 105.48$
рдПрдХूрдг рдХिंрдордд = рдХрд░рдкाрдд्рд░ рдХिंрдордд + GST
рдПрдХूрдг рдХिंрдордд = $586 + 105.48 = 691.48$
рдЧ्рд░ाрд╣рдХाрд╕ाрдаी рдХिंрдордд = 691.48 рд░ुрдкрдпे
(v) рдПрдХा рдХुрдЯुंрдмाрдЪ्рдпा рд╡ाрд░्рд╖िрдХ рдЧुंрддрд╡рдгुрдХीрдЪा рд╡ृрдд्рддाрд▓ेрдЦ рджिрд▓ा рдЖрд╣े. рд╢ेрдЕрд░्рд╕: $60^\circ$, рд╕्рдеाрд╡рд░ рдоाрд▓рдордд्рддा: $120^\circ$, рдо्рдпुрдЪ्рдпुрдЕрд▓ рдлंрдб: $60^\circ$, рдмँрдХेрддीрд▓ рдаेрд╡: $90^\circ$, рдкोрд╕्рдЯ: $30^\circ$. рдЬрд░ рд╢ेрдЕрд░्рд╕рдордзीрд▓ рдЧुंрддрд╡рдгूрдХ 2,000 рд░ुрдкрдпे рдЕрд╕ेрд▓, рддрд░ рдПрдХूрдг рдЧुंрддрд╡рдгूрдХ рдЖрдгि рдкोрд╕्рдЯाрддीрд▓ рдЧुंрддрд╡рдгूрдХ рдХाрдвा.
(a) рд╢ेрдЕрд░्рд╕рд╕ाрдаी рдХेंрдж्рд░ीрдп рдХोрди = $\frac{\text{рд╢ेрдЕрд░्рд╕рдордзीрд▓ рдЧुंрддрд╡рдгूрдХ}}{\text{рдПрдХूрдг рдЧुंрддрд╡рдгूрдХ}} \times 360^\circ$
$60^\circ = \frac{2000}{\text{рдПрдХूрдг}} \times 360^\circ$
$\text{рдПрдХूрдг рдЧुंрддрд╡рдгूрдХ} = \frac{2000 \times 360}{60} = 2000 \times 6 = 12,000$

(b) рдкोрд╕्рдЯाрддीрд▓ рдЧुंрддрд╡рдгूрдХ:
рдкोрд╕्рдЯाрдЪा рдХोрди = $30^\circ$
$\text{рд░рдХ्рдХрдо} = \frac{30}{360} \times 12,000 = \frac{1}{12} \times 12,000 = 1,000$
рдПрдХूрдг рдЧुंрддрд╡рдгूрдХ = 12,000 рд░ुрдкрдпे; рдкोрд╕्рдЯाрддीрд▓ рдЧुंрддрд╡рдгूрдХ = 1,000 рд░ुрдкрдпे
рдк्рд░рд╢्рди рей. (A) рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддीрд╣ी рдПрдХ рдХृрддी рдкूрд░्рдг рдХрд░ूрди рд▓िрд╣ा : (рей рдЧुрдг)
(i) рдПрдХा рд╢ेрдЕрд░рдЪा рдмाрдЬाрд░рднाрд╡ 1,000 рд░ुрдкрдпे рдЕрд╕рддाрдиा рддो рд╢ेрдЕрд░ рд╡िрдХрд▓ा рд╡ рдд्рдпाрд╡рд░ 0.1% рджрд▓ाрд▓ी рджिрд▓ी рддрд░ рд╡िрдХ्рд░ीрдиंрддрд░ рдоिрд│рдгाрд░ी рд░рдХ्рдХрдо рдХाрдвा.
рджрд▓ाрд▓ी рд░рдХ्рдХрдо = рдмाрдЬाрд░рднाрд╡ $\times$ рджрд▓ाрд▓ीрдЪा рджрд░
$= 1000 \times \frac{0.1}{\boxed{100}}$
$= 10 \times 0.1 = \boxed{1}$
рд╡िрдХ्рд░ीрдиंрддрд░ рдоिрд│рдгाрд░ी рд░рдХ्рдХрдо = рдмाрдЬाрд░рднाрд╡ - рджрд▓ाрд▓ी
$= 1000 - \boxed{1}$
$= \boxed{999} \text{ рд░ुрдкрдпे.}$
(ii) рдПрдХा рдлाрд╢ाрдЪ्рдпा рдкृрд╖्рдарднाрдЧाрд╡рд░ 2, 4, 6, 8, 10, 12 рдпा рд╕ंрдЦ्рдпा рдЖрд╣ेрдд. рд╣ा рдлाрд╕ा рдПрдХрджा рдлेрдХрд▓ा рддрд░ рд╡рд░рдЪ्рдпा рдкृрд╖्рдарднाрдЧाрд╡рд░ рдоिрд│рдгाрд░ी рд╕ंрдЦ्рдпा рдкूрд░्рдг рд╡рд░्рдЧ рдЕрд╕рдг्рдпाрдЪी рд╕ंрднाрд╡्рдпрддा рдХाрдвा.
$S = \{2, 4, 6, 8, 10, 12\}$
$n(S) = \boxed{6}$
рдШрдЯрдиा B: рд╕ंрдЦ्рдпा рдкूрд░्рдг рд╡рд░्рдЧ рдЕрд╕рдгे. рдлрдХ्рдд 4 рд╣ी рдкूрд░्рдг рд╡рд░्рдЧ рд╕ंрдЦ्рдпा рдЖрд╣े ($2^2$).
$B = \{ \boxed{4} \}$
$n(B) = \boxed{1}$
$P(B) = \frac{n(B)}{n(S)} = \frac{\boxed{1}}{6}$
рдк्рд░рд╢्рди рей. (B) рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддेрд╣ी рджोрди рдЙрдкрдк्рд░рд╢्рди рд╕ोрдбрд╡ा : (рем рдЧुрдг)
(i) рдЦाрд▓ीрд▓ рдПрдХрд╕ाрдордпिрдХ рд╕рдоीрдХрд░рдгे рдХ्рд░ेрдорд░рдЪ्рдпा рдкрдж्рдзрддीрдиे рд╕ोрдбрд╡ा : $4m-2n=-4; 4m+3n=16$.
$D = \begin{vmatrix}4 & -2 \\ 4 & 3\end{vmatrix} = (12) - (-8) = 20$
$D_m = \begin{vmatrix}-4 & -2 \\ 16 & 3\end{vmatrix} = (-12) - (-32) = 20$
$D_n = \begin{vmatrix}4 & -4 \\ 4 & 16\end{vmatrix} = (64) - (-16) = 80$
$m = \frac{D_m}{D} = \frac{20}{20} = 1$
$n = \frac{D_n}{D} = \frac{80}{20} = 4$
рдЙрдХрд▓: (m, n) = (1, 4)
(ii) рдЦाрд▓ीрд▓ рд╡рд░्рдЧрд╕рдоीрдХрд░рдг рд╕ूрдд्рд░ाрдЪा рд╡ाрдкрд░ рдХрд░ूрди рд╕ोрдбрд╡ा : $y^{2}+\frac{1}{3}y=2$
3 рдиे рдЧुрдгूрди: $3y^2 + y = 6 \Rightarrow 3y^2 + y - 6 = 0$
$a=3, b=1, c=-6$
$b^2 - 4ac = (1)^2 - 4(3)(-6) = 1 + 72 = 73$
$y = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$
$y = \frac{-1 \pm \sqrt{73}}{6}$
рдоुрд▓े: $\frac{-1+\sqrt{73}}{6}, \frac{-1-\sqrt{73}}{6}$
(iii) рджोрди рдлाрд╕े рдПрдХाрдЪ рд╡ेрд│ी рдлेрдХрд▓े рдЕрд╕рддा рдирдоुрдиा рдЕрд╡рдХाрд╢ 'S' рд╡ $n(S)$ рд▓िрд╣ा. рддрд╕ेрдЪ рдШрдЯрдиा A рдЖрдгि B рд▓िрд╣ा.
$S = \{(1,1)...(6,6)\}$, $n(S) = 36$.
рдШрдЯрдиा A: рдЕंрдХांрдЪी рдмेрд░ीрдЬ 5 рдЪ्рдпा рдкрдЯीрдд рдЖрд╣े.
рдмेрд░ीрдЬ 5 рдХिंрд╡ा 10 рдЕрд╕ू рд╢рдХрддे.
$A = \{(1,4), (2,3), (3,2), (4,1), (4,6), (5,5), (6,4)\}$
$n(A) = 7$

рдШрдЯрдиा B: рдЕंрдХांрдЪी рдмेрд░ीрдЬ 25 рдЖрд╣े.
рдЬाрд╕्рддीрдд рдЬाрд╕्рдд рдмेрд░ीрдЬ 12 (6+6) рдЕрд╕рддे. рдмेрд░ीрдЬ 25 рдЕрд╢рдХ्рдп рдЖрд╣े.
$B = \{ \}$ (рд░िрдХ्рдд рд╕ंрдЪ)
$n(B) = 0$
рдк्рд░рд╢्рди рек. рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддेрд╣ी рджोрди рдЙрдкрдк्рд░рд╢्рди рд╕ोрдбрд╡ा : (рео рдЧुрдг)
(i) рдЯोрд▓рдиाрдХ्рдпाрд╡рд░ рдЬрдоा рд╣ोрдгाрд░ा рдХрд░ (рд░ुрдкрдпांрдд) рд╡ рд╡ाрд╣рди рд╕ंрдЦ्рдпा рджिрд▓ी рдЖрд╣े. рдд्рдпाрд╡рд░ूрди рдЬрдоा рд╣ोрдгाрд▒्рдпा рдХрд░ाрдЪे 'рдЧृрд╣ीрддрдордз्рдп' рдкрдж्рдзрддीрдиे рдордз्рдп рдХाрдвा.
рдЧृрд╣ीрддрдордз्рдп $A = 550$ рдоाрдиू (500-600 рдЪा рд╡рд░्рдЧрдордз्рдп).
рд╡рд░्рдЧ (рдХрд░) рд╡рд░्рдЧрдордз्рдп ($x_i$) $d_i = x_i - 550$ рд╡ाрд░ंрд╡ाрд░рддा ($f_i$) $f_i d_i$
300-400350-20080-16000
400-500450-100110-11000
500-60055001200
600-700650100707000
700-800750200408000
рдПрдХूрдг $\sum f_i = 420$ $\sum f_i d_i = -12000$
$\bar{d} = \frac{\sum f_i d_i}{\sum f_i} = \frac{-12000}{420} \approx -28.57$
рдордз्рдп $\bar{X} = A + \bar{d} = 550 + (-28.57) = 521.43$
рд╕рд░ाрд╕рд░ी рдХрд░ = 521.43 рд░ुрдкрдпे
(ii) рдордиीрд╖ाрд▓ा 540 рдХेрд│ी рдХाрд╣ी рд╡िрдж्рдпाрд░्рде्рдпांрдиा рд╕рдоाрди рд╡ाрдЯाрдпрдЪी рдЖрд╣ेрдд. рдЬрд░ 30 рд╡िрдж्рдпाрд░्рдеी рдЬाрд╕्рдд рдЕрд╕рддे рддрд░ рдк्рд░рдд्рдпेрдХाрд▓ा 3 рдХेрд│ी рдХрдоी рдоिрд│ाрд▓ी рдЕрд╕рддी. рддрд░ рд╡िрдж्рдпाрд░्рде्рдпांрдЪी рд╕ंрдЦ्рдпा рдХाрдвा.
рд╕рдордЬा рд╡िрдж्рдпाрд░्рде्рдпांрдЪी рдоूрд│ рд╕ंрдЦ्рдпा = $x$. рдк्рд░рдд्рдпेрдХाрд▓ा рдоिрд│рдгाрд░ी рдХेрд│ी = $540/x$.
рдирд╡ीрди рд╡िрдж्рдпाрд░्рдеी рд╕ंрдЦ्рдпा = $x+30$. рдирд╡ीрди рдХेрд│ी рд╕ंрдЦ्рдпा = $540/(x+30)$.
рдЕрдЯ: рдЬुрдиे рд╡ाрдЯрдк - рдирд╡ीрди рд╡ाрдЯрдк = 3
$\frac{540}{x} - \frac{540}{x+30} = 3$
3 рдиे рднाрдЧूрди: $\frac{180}{x} - \frac{180}{x+30} = 1$
$180(x+30) - 180x = x(x+30)$
$180x + 5400 - 180x = x^2 + 30x$
$x^2 + 30x - 5400 = 0$
5400 рдЪे рдЕрд╡рдпрд╡ рдЬ्рдпांрдЪा рдлрд░рдХ 30 рдЖрд╣े: 90 рдЖрдгि 60.
$(x+90)(x-60) = 0$
$x = 60$ (рд╡िрдж्рдпाрд░्рдеी рд╕ंрдЦ्рдпा рдЛрдг рдЕрд╕ू рд╢рдХрдд рдиाрд╣ी).
рд╡िрдж्рдпाрд░्рде्рдпांрдЪी рд╕ंрдЦ्рдпा = 60
(iii) 2,000 рд░ुрдкрдпांрдЪी рд░рдХ्рдХрдо 10% рд╕рд░рд│рд╡्рдпाрдЬ рджрд░ाрдиे рдЧुंрддрд╡рд▓ी, рддрд░ рд╡्рдпाрдЬाрдЪी рд░рдХ्рдХрдо рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рд╣ोрдИрд▓ рдХा рддे рддрдкाрд╕ा. 10 рд╡рд░्рд╖ाрдиंрддрд░ рдоिрд│рдгाрд▒्рдпा рд╡्рдпाрдЬाрдЪी рд░рдХ्рдХрдо рдХाрдвा.
рдоुрдж्рджрд▓ = 2000, рджрд░ = 10%.
рд╡рд░्рд╖ 1 рдЪे рд╡्рдпाрдЬ: $(2000 \times 10 \times 1)/100 = 200$
рд╡рд░्рд╖ 2 рдЪे рд╡्рдпाрдЬ: $(2000 \times 10 \times 2)/100 = 400$
рд╡рд░्рд╖ 3 рдЪे рд╡्рдпाрдЬ: 600...
рдХ्рд░рдоिрдХा: 200, 400, 600...
рд╕ाрдоाрди्рдп рдлрд░рдХ $d = 200$ рд╕्рдеिрд░ рдЖрд╣े. рдо्рд╣рдгूрди рд╣ी рдЕंрдХрдЧрдгिрддीрдп рд╢्рд░ेрдвी рдЖрд╣े.
10 рд╡рд░्рд╖ाрдиंрддрд░рдЪे рд╡्рдпाрдЬ ($t_{10}$):
$t_{10} = a + 9d = 200 + 9(200) = 200 + 1800 = 2000$.
10 рд╡рд░्рд╖ाрдиंрддрд░ рдоिрд│рдгाрд░े рд╡्рдпाрдЬ = 2,000 рд░ुрдкрдпे
(iv) [рд╕ांрдЦ्рдпिрдХी - рдмрд╣ुрд▓рдХ] рд╡рд░्рдЧीрдХृрдд рд╡ाрд░ंрд╡ाрд░рддा рд╕ाрд░рдгी рддрдпाрд░ рдХрд░ा рдЖрдгि рдмрд╣ुрд▓рдХ рдХाрдвा.
рджिрд▓ेрд▓ी рдоाрд╣िрддी: 0-20 (10%), 20-40 (20%), 40-60 (35%), 60-80 (20%), 80-100 (рдЙрд░рд▓ेрд▓े 30 рд╡िрдж्рдпाрд░्рдеी).
рдПрдХूрдг рдЯрдХ्рдХेрд╡ाрд░ी = $10+20+35+20 = 85\%$. рдЙрд░рд▓ेрд▓े = $15\%$.
рдЬрд░ $15\% = 30$ рд╡िрдж्рдпाрд░्рдеी, рддрд░ рдПрдХूрдг рд╡िрдж्рдпाрд░्рдеी $N = (30/15) \times 100 = 200$.
рд╡ाрд░ंрд╡ाрд░рддा рд╕ाрд░рдгी:
0-20: $10\% \text{ of } 200 = 20$
20-40: $20\% \text{ of } 200 = 40$ ($f_0$)
40-60: $35\% \text{ of } 200 = 70$ ($f_1$ - рдмрд╣ुрд▓рдХीрдп рд╡рд░्рдЧ)
60-80: $20\% \text{ of } 200 = 40$ ($f_2$)
80-100: 30

рдмрд╣ुрд▓рдХ:
рдмрд╣ुрд▓рдХीрдп рд╡рд░्рдЧ: 40-60. $L=40, h=20, f_1=70, f_0=40, f_2=40$.
рдмрд╣ुрд▓рдХ $= L + [\frac{f_1-f_0}{2f_1-f_0-f_2}] \times h$
$= 40 + [\frac{70-40}{140-40-40}] \times 20$
$= 40 + [\frac{30}{60}] \times 20$
$= 40 + 10 = 50$
рдмрд╣ुрд▓рдХ = 50 рдЧुрдг
рдк्рд░рд╢्рди рел. рдЦाрд▓ीрд▓рдкैрдХी рдХोрдгрддाрд╣ी рдПрдХ рдЙрдкрдк्рд░рд╢्рди рд╕ोрдбрд╡ा : (рей рдЧुрдг)
(i) рдкुрдвीрд▓ рд╕ाрдордЧ्рд░ी рдЖрдпрддाрд▓ेрдЦाрдж्рд╡ाрд░े рджрд░्рд╢рд╡ा :
рджिрд▓ेрд▓ी рдоाрд╣िрддी: 60-80 (4), 80-100 (12), 100-120 (16), 120-140 (8).
Draw histogram of the following data:Data given: 60-80 (4), 80-100 (12), 100-120 (16), 120-140 (8). рдЯीрдк: рдпाрд╕ाрдаी рдЖрд▓ेрдЦ рдХाрдврдгे рдЖрд╡рд╢्рдпрдХ рдЖрд╣े. X-рдЕрдХ्рд╖ाрд╡рд░ 'рдмुрдж्рдзрдпांрдХ' рдЖрдгि Y-рдЕрдХ्рд╖ाрд╡рд░ 'рд╡िрдж्рдпाрд░्рдеी рд╕ंрдЦ्рдпा' рдШेрдКрди рд╕рд▓рдЧ рд╕्рддंрдн рдХाрдвाрд╡ेрдд.
(ii) рдЖрдХृрддीрдордз्рдпे рджिрд▓ेрд▓्рдпा рдоाрд╣िрддीрд╡рд░ूрди рдЖрдпрддाрдЪी рд▓ांрдмी рд╡ рд░ुंрджी рдХाрдвा.
Find length and breadth of rectangle using given figure
рдЖрдпрддाрдЪ्рдпा рд╕рдоोрд░ाрд╕рдоोрд░рдЪ्рдпा рдмाрдЬू рд╕рдоाрди рдЕрд╕рддाрдд.
1) $2m + 3n + 5 = 5m + n$
$5m - 2m + n - 3n = 5$
$3m - 2n = 5$ ... (I)

2) $3m - 2n + 7 = m + n - 3$
$3m - m - 2n - n = -3 - 7$
$2m - 3n = -10$ ... (II)

рд╕рдоीрдХрд░рдг (I) рд▓ा 3 рдиे рдЖрдгि (II) рд▓ा 2 рдиे рдЧुрдгू:
$9m - 6n = 15$
$4m - 6n = -20$
рд╡рдЬाрдмाрдХी рдХрд░ूрди: $5m = 35 \Rightarrow m = 7$.

m=7 рд╕рдоीрдХрд░рдг (I) рдордз्рдпे рдаेрд╡ू:
$3(7) - 2n = 5$
$21 - 5 = 2n$
$16 = 2n \Rightarrow n = 8$.

рдЖрдпрддाрдЪी рдоाрдкे:
рд▓ांрдмी $= 5m + n = 5(7) + 8 = 35 + 8 = 43$.
рд░ुंрджी $= m + n - 3 = 7 + 8 - 3 = 12$.
рд▓ांрдмी = 43 рд╕ेрдоी, рд░ुंрджी = 12 рд╕ेрдоी
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HSC English July 2024 Board Paper Solution Maharashtra

BOARD ACTIVITY SHEET: JULY 2024

ENGLISH YUVAKBHARATI | Max Marks: 80 | Time: 3 Hrs
SECTION – I: PROSE
(Reading for Comprehension, Language Study, Summary and Mind Mapping)
Q. 1. (A) Read the extract and complete the activities given below:

(Extract Source: "Voyaging Towards Excellence" by Achyut Godbole)

A1. Read and rewrite the following sentences and state whether they are True or False: (2 Marks)
  1. The narrator chose a career in writing over his career in software companies.
    Answer: True
  2. The narrator’s success is determined by the sale of his books.
    Answer: False
  3. His autobiography has proved itself as a good remedy on depression.
    Answer: True
  4. The passage ends on a positive note.
    Answer: True
A2. Give reasons: (2 Marks)
  1. The writer could be commercially successful because he had offers of around 3 crore rupees per annum.
  2. The writer is telling his story to the readers because there are a number of lessons and values that he cherishes and keeps learning about even today.
A3. Interpret the following statement from the extract: (2 Marks)

“It is these reactions of thousands of readers and the feeling that I am touching the hearts of thousands of my readers, that keeps me going...”

Answer: The statement implies that the writer's true motivation comes from the emotional impact his work has on people, rather than financial gain. Knowing that his books help readers navigate life's challenges, such as depression or suicide, gives him the energy and purpose to continue writing.
A4. Write a few sentences about your ‘dream career.’ (2 Marks)
Answer: My dream career is to become a software engineer. I am passionate about technology and problem-solving. I want to develop applications that simplify daily tasks and contribute to the digital advancement of society.
A5. Do as directed: (2 Marks)

(i) I wanted to return to my first love. (Frame a ‘wh’ question to get the underlined part as the answer.)

Options:
(a) Where did I wanted to return?
(b) Where do I want to return?
(c) Where did I want to return?
(d) Why did I want to return?

Correct Answer: (c) Where did I want to return?


(ii) My book ‘Boardroom’ on management has created at least 20 successful entrepreneurs. (Choose the correct passive voice form)

Options:
(a) At least 20 successful entrepreneurs will be created by my book ‘Boardroom’ on management.
(b) At least 20 successful entrepreneurs have been created by my book ‘Boardroom’ on management.
(c) At least 20 successful entrepreneurs has been created by my book ‘Boardroom’ on management.
(d) At least 20 successful entrepreneurs are created by my book ‘Boardroom’ on management.

Correct Answer: (b) At least 20 successful entrepreneurs have been created by my book ‘Boardroom’ on management.

A6. Rewrite the given sentences with the appropriate word given in the bracket: (2 Marks)

(existence, management, entrepreneurs, rationally, symphony, autobiography)

  1. There is no human existence on Mars.
  2. Symphony of emotions make a relation musical.
  3. ‘My experiments With Truth’ is a famous autobiography.
  4. Time management is very significant during examination.
B1. Language study - Do as directed: (3 Marks)

(i) I can teach four languages including French. (Choose the correct option replacing the modal auxiliary showing ‘compulsion’.)

Correct Answer: (c) I must teach four languages including French.

(ii) Netra is always interested in school excursions. (Choose the correct Rhetorical question form.)

Correct Answer: (d) Isn’t Netra always interested in school excursions?

(iii) There are many people who had a desire to speak ‘correct’ English. (Choose the correct simple sentence form.)

Correct Answer: (b) Many people have a desire to speak ‘Correct’ English.

B2. Spot the error and rewrite correct sentence: (1 Mark)

English movies has entertained the world.

Answer: English movies have entertained the world.
Q. 2. (A) Read the following extract and complete the activities given below: (12 Marks)

(Extract Source: Green Belt Movement / Wangari Maathai)

A1. Complete the web diagram on ‘the impacts of environmental degradation’: (2 Marks)
Center: Impacts of Environmental degradation

1. Lack of firewood, clean drinking water, and balanced diets
2. Scramble for scarce resources
3. Poverty and even conflict
4. Incapacity to sustain families / Malnutrition

12th English Board Papers

A2. Provide the supporting details from the extract that highlight the positive effects of tree plantation: (2 Marks)
Positive effects of tree plantation (1) It is simple, attainable and guarantees quick, successful results.
(2) It sustains interest and commitment within a reasonable amount of time.
(3) Trees provide fuel, food, shelter, and income to support education and needs.
(4) The activity creates employment and improves soil and watersheds.
A3. Environmental degradation and mismanagement affect the life in rural Kenya. Explain. (2 Marks)
Answer: Environmental degradation leads to a scarcity of basic resources like firewood, clean water, and balanced diets. This places a heavy burden on rural women who are the primary caretakers. It results in malnutrition, poverty, and conflict over scarce resources, making it difficult for families to sustain themselves.
A4. Suggest some ways to protect your local environment. (2 Marks)
Answer:
  • Plant more trees and maintain existing green cover.
  • Reduce the use of single-use plastics and encourage recycling.
  • Conserve water by rainwater harvesting and fixing leaks.
  • Spread awareness about waste segregation and composting.
A5. Language Study - Do as directed: (2 Marks)

(i) Tree planting became a natural choice. (Find out the correct option in which ‘Present Perfect Tense’ is used.)

Correct Answer: (b) Tree planting has become a natural choice.

(ii) They were unable to meet their basic needs. (Choose the correct ‘Negative sentence’ - Note: The instruction implies rewriting with 'not' while keeping the meaning or simply finding the negative form.)

Correct Answer: (c) They were not able to meet their basic needs.

A6. Vocabulary: (2 Marks)

Find out the words from the extract which mean-

  1. extremely painful: excruciating
  2. all forms of life on earth: bio-diversity
  3. act of stealing/removing: plundered
  4. the action of making impure by polluting: contamination
Q. 2. (B) Summarising: (3 Marks)

Write a ‘summary’ of the above extract by using the following points.

The Green Belt Movement: Restoring Hope

The extract highlights the severe impact of commercial farming in rural Kenya, which destroyed local biodiversity and forests. This led to a scarcity of essentials like firewood and water, causing poverty, malnutrition, and conflict. To combat this, Wangari Maathai introduced tree planting as a simple yet effective solution. This initiative not only provided fuel, food, and income but also empowered the community, improved the soil, and helped restore the environment, thereby securing the future for the families.

Q. 2. (C) Mind Mapping: (3 Marks)

Prepare a mind map on the topic “Disadvantages of smartphone” using your ideas.

Main Topic: Disadvantages of Smartphone
  • Health Issues
    • Eye strain / Vision problems
    • Poor posture (Text neck)
    • Sleep disruption
  • Social Impact
    • Reduced face-to-face interaction
    • Cyberbullying
    • Social isolation
  • Distraction
    • Poor academic performance
    • Reduced productivity
    • Accidents while driving
  • Security Risks
    • Data theft
    • Hacking
    • Loss of privacy
SECTION II: POETRY
(Poetry and Appreciation)
Q. 3. (A) Read the extract and complete the activities given below: (10 Marks)

(Poem: "Money" by William H. Davies)

A1. Compare the lifestyle of the rich and poor people: (2 Marks)
Rich people Poor people
(i) They have many false friends who visit only for their wealth. (i) Their hearts are light and free from the anxiety of wealth.
(ii) They feel fear and worry, often frowning coldly. (ii) They are content, and their wives hum like bees while working.
A2. Explain the reasons for which many false friends came knocking at the poet’s door. (2 Marks)
Answer: Many false friends came knocking at the poet's door because he had money. These people were attracted solely by his wealth and status, pretending to be friends to gain material benefits, rather than having any genuine affection for him.
A3. Define, ‘Friendship’ in your own words. (2 Marks)
Answer: Friendship is a selfless bond of trust, support, and mutual affection between individuals. True friendship remains constant during both good and bad times and is not influenced by material wealth or social status.
A4. Name and explain the figure of speech in the following line: (2 Marks)

‘Much have I thought of life, and seen’

Answer: Inversion.
Explanation: The word order is changed for poetic effect. The correct prose order is "I have thought and seen much of life."
A5. Compose four poetic lines of your own on ‘happiness.’ (2 Marks)
Answer:
Happiness lies not in gold or greed,
But in helping a friend in need.
A simple life with love to share,
Is the true wealth beyond compare.
Q. 3. (B) Appreciation: (4 Marks)

Read the extract and write the appreciation of the poem given below: (Poem: Father Returning Home)

Title: Father Returning Home
Poet: Dilip Chitre

Theme: The poem deals with the themes of alienation, loneliness, and the generation gap in modern urban life. It portrays the dull, monotonous routine of an elderly father who feels isolated even within his own family.

Poetic Devices: The poet uses vivid Imagery (e.g., "yellow light", "soggy shirt", "muddy bag") to create a gloomy atmosphere. Simile is used effectively in the line "Like a word dropped from a long sentence" to highlight the father's insignificance. Alliteration is seen in "suburbs slide".

Message: The poem conveys the painful reality of the elderly who are neglected by the younger generation. It highlights how urbanization has eroded emotional bonds, leaving individuals isolated in a crowd.

Opinion: I find the poem very touching and realistic. It serves as a mirror to society, urging us to be more compassionate towards our parents and the elderly.

SECTION III: WRITING SKILLS
Q. 4. Complete the activities as per the instructions given below: (16 Marks)
(A) Attempt ‘Any One’ of the following activities: (4 Marks)

(i) Drafting a virtual message:

Question: Imagine, Sunny has been selected to appear in the final round of the singing competition. Sunny’s father has moved out of the city for some official work. Sunny tried to call his father several times. But, due to the connectivity issues, he is unable to contact his father. Draft a virtual message in about 50 words to convey this information/news to his father.

Date: 25th July 2024     Time: 4:00 PM

Dear Dad,

I have great news! I have been selected for the final round of the singing competition. I tried calling you to share this happiness, but couldn't get through due to network issues. I am very excited and wanted you to know immediately. Hope your work trip is going well.

Love,
Sunny

OR

(ii) Statement of Purpose:

Question: Imagine you wish to pursue a Bachelor’s degree in ‘Communication Skills,’ at a reputed university in India or abroad to enhance your career in corporate correspondence. Prepare a statement of purpose in about 150 words which will help you to get admission in your dream university.

Statement of Purpose

Communication is the bridge between confusion and clarity. From a young age, I have been fascinated by how words shape perceptions and drive decisions. As a student of the Commerce stream, I realized that technical knowledge is futile without the ability to articulate it effectively. This realization has driven my desire to pursue a Bachelor’s degree in Communication Skills at your esteemed university.

My academic journey has been consistent, with a strong focus on languages and social sciences. I have actively participated in debates and served as the editor of my school magazine, which honed my writing and public speaking abilities. However, to thrive in the dynamic world of corporate correspondence, I need professional training.

Your university offers a curriculum that perfectly blends theory with practical exposure. I am particularly interested in your modules on Digital Media and Corporate Rhetoric. I am confident that this course will equip me with the necessary skills to become a proficient corporate communicator. I am eager to contribute to and learn from the diverse student community at your institution.

OR

(iii) Group Discussion:

Question: Imagine the XII class students attended a presentation on “writing skill” conducted by a distinguished personality. Write a group discussion in the form of dialogues associated with this presentation among 3/4 student participants.

Topic: Reflections on the "Writing Skill" Presentation

Participants: Rahul, Priya, Amit, and Sneha.

Rahul: Hi everyone, today's session on writing skills was really eye-opening, wasn't it? I never realized that 'brevity is the soul of wit' applies so strictly to corporate writing.

Priya: Absolutely, Rahul. I liked the point the speaker made about knowing your audience. I used to think using complex vocabulary was impressive, but he clarified that simplicity connects better.

Amit: That’s true. However, I felt he focused too much on formal writing. I wish he had covered creative writing a bit more. What do you think, Sneha?

Sneha: I agree with Amit to an extent, but since it was geared towards future careers, the formal aspect was necessary. My takeaway was the importance of proofreading. I often skip that step.

Rahul: Valid point, Sneha. The 'Draft-Edit-Polish' technique he explained is something I’m definitely going to apply in our upcoming English project.

Priya: Agreed. Overall, it was a very productive session. It changed my perspective on how to structure thoughts on paper.

(B) Attempt ‘Any One’ of the following activities: (4 Marks)

(i) E-mail:

Question: Imagine your housing colony wishes to organise a programme in view of ‘World Ozone Day.’ As the secretary of the colony, draft an email to a distinguished personality to invite him as a chief guest for the same.

To: dr.kulkarni.env@scienceforum.org
Subject: Invitation as Chief Guest for 'World Ozone Day' Awareness Programme

Respected Dr. Kulkarni,

I hope this email finds you well. I am writing to you in my capacity as the Secretary of Sunrise Housing Society, Pune.

We are organizing a community awareness programme on the occasion of 'World Ozone Day' on 16th September 2024. The event aims to educate our residents, particularly the youth, about the importance of the ozone layer and sustainable living practices.

Knowing your vast contribution to Environmental Science and your inspiring work in climate preservation, it would be a distinct honor for us to have you as our Chief Guest. We would be grateful if you could address the gathering and share your valuable insights.

The event is scheduled from 10:00 AM to 12:00 PM at our Society Clubhouse. We look forward to a positive response.

Warm Regards,
Rohan Deshmukh
Secretary, Sunrise Housing Society

OR

(ii) Report Writing:

Question: Imagine your college recently organised a programme on ‘Personality Development.’ As a student incharge, write a report of the same in about 150 words for your college magazine.

Personality Development Workshop: Unlocking Potential

- By Student Incharge, Class XII

Mumbai, July 20: Ideally College organized a dynamic one-day workshop on ‘Personality Development’ on 18th July 2024 in the college auditorium. The objective was to groom students for future professional challenges and enhance their soft skills.

The programme began at 9:00 AM with the lighting of the lamp by the Principal, Dr. A. Joshi. The keynote speaker was Mr. Vikram Singh, a renowned corporate trainer. He conducted interactive sessions on body language, effective communication, and time management. He emphasized that personality is not just about external appearance but about character, confidence, and attitude.

Around 200 students from the Commerce and Arts streams participated. Activities like mock interviews and role-plays were the highlights, helping students overcome stage fear. The session concluded with a Q&A round where students cleared their doubts regarding career etiquette.

The workshop was a resounding success, leaving students motivated and better equipped to face the competitive world.

OR

(iii) Interview:

Question: Imagine you wish to conduct an interview of a ‘social worker.’ With the help of the format given below, draft questions on the given fields. (Format: Name, Field, Date/Time/Duration, Questions on: Early interests, Challenges, Role models, Achievements, Feedback, Family support, Govt support, Future plans).

Name of the interviewee: Mrs. Sindhu Sapkal (Hypothetical)
Field/Reputation: Child Welfare and Orphanage Management
Date/Venue/Time: 25th July 2024, Sanmati Bal Niketan, 11:00 AM
Duration: 45 Minutes

Questions:

  1. Early interests: What inspired you to choose social work as your path at such a young age?
  2. Challenges faced: What were the biggest hurdles you faced when you first started this orphanage?
  3. Role model/s: Who has been your biggest inspiration or mentor in this journey of service?
  4. Achievements/Awards: You have received numerous awards; which one is closest to your heart and why?
  5. Family support: How did your family react when you decided to dedicate your life to social service?
  6. Government support: Do you think the government schemes for child welfare are sufficient, or is more support needed?
  7. Feedback: How does it feel when the children you raised return as successful adults to help the organization?
  8. Future plans: What is your vision for the organization for the next five years?
(C) Attempt ‘Any One’ of the following activities: (4 Marks)

(i) Speech:

Question: Imagine you wish to participate in an intercollegiate elocution competition. You have selected ‘Should we keep pets?’ as your topic for your speech. Draft a speech in about 150 words on this topic.

Honorable Judges, Teachers, and my dear friends,

A very good morning to all. Today, I stand before you to speak on the topic, "Should we keep pets?"

In a world that is becoming increasingly digital and disconnected, pets serve as a bridge to nature and unconditional love. Keeping a pet—whether a dog, cat, or hamster—is not just a hobby; it is a lesson in humanity. Pets teach us responsibility, empathy, and patience. Scientific studies have proven that the company of animals reduces stress, lowers blood pressure, and alleviates loneliness.

However, we must ask ourselves: are we ready for them? Keeping a pet is a lifelong commitment. It requires time, financial resources, and emotional investment. If we keep pets merely for status or entertainment without caring for their needs, it is cruel.

So, should we keep pets? My answer is a resounding 'Yes,' but only if we are willing to treat them as family members. They don't just need a home; they need a heart to live in.

Thank you.

OR

(ii) Compering:

Question: Imagine your college is organising a programme to celebrate ‘Teacher’s Day.’ You are given the responsibility to compere at the programme. Prepare the programme script deciding the flow of the whole programme. (Points: prayer, welcome, introduction, felicitation, speeches, vote of thanks).

1. Introduction & Welcome:
"Good morning to our Respected Principal, beloved teachers, and enthusiastic students! Today is a special day where we celebrate the guiding lights of our lives. Welcome to the Teacher's Day celebration of 2024!"

2. Prayer:
"To begin this auspicious occasion, let us invoke the blessings of the Almighty. I request the college choir to come forward for the prayer song. (Prayer follows...)"

3. Introduction of the Function:
"Dr. Sarvepalli Radhakrishnan said, 'Teachers should be the best minds in the country.' Today, we honor the dedication and hard work of our teachers who mold us into better citizens."

4. Felicitation:
"I now request our Student Council President to felicitate our Principal and teachers with a token of our love and appreciation—a rose and a handmade card."

5. Speeches:
"Now, I would like to invite Miss Anjali from Class XII to share her thoughts on behalf of the students... (After speech) Thank you, Anjali. Now, may I request our Principal Sir to address the gathering."

6. Vote of Thanks:
"As we come to the end of this beautiful ceremony, I call upon Mr. Rohit to propose the vote of thanks. Thank you, teachers, for everything. Happy Teacher's Day!"

OR

(iii) Expansion of Idea:

Question: Expand the following idea with the help of the points given below (100 to 150 words): ‘The wise man has long ears and a short tongue.’ (Points: One should be a good listener, Listening adds to your knowledge, Speaking to the point catches attention).

The Wise Man Has Long Ears and a Short Tongue

There is a reason why nature has given us two ears but only one tongue; it is so that we may listen twice as much as we speak. This proverb highlights the virtue of listening over excessive talking.

A wise person understands that speaking only repeats what one already knows, whereas listening opens the door to new knowledge. "Long ears" symbolize patience and the willingness to absorb information, understand different perspectives, and empathize with others. "A short tongue" represents brevity and discretion. Speaking less prevents one from saying foolish or regretful things.

In today's world, everyone wants to be heard, but few want to listen. Great leaders and thinkers are often great listeners. When we speak to the point, our words carry weight and command respect. Therefore, wisdom lies in observing silence, listening deeply, and speaking only when necessary and valuable.

(D) Attempt ‘Any One’ of the following activities: (4 Marks)

(i) Review:

Question: You have recently read a ‘Book’/‘Magazine.’ Write a ‘Review’ on the same with the help of the following points: Title/Contents, Objectives/Features/Characteristics, Presentation/Creativity/Novelty, Personal views/Opinion/Evaluation.

Book Review: "Wings of Fire"

Title & Author: "Wings of Fire" is the autobiography of Dr. A.P.J. Abdul Kalam, written with Arun Tiwari.

Contents & Theme: The book narrates the journey of a young boy from Rameswaram who overcame humble beginnings to become a premier scientist and the President of India. It covers his early life, his work at ISRO and DRDO, and the development of the Agni and Prithvi missiles.

Presentation & Style: The narrative is simple yet powerful. It is not just technical but deeply spiritual and patriotic. The inclusion of photos and poems adds a personal touch to the scientific journey.

Personal Opinion: This book is a beacon of hope. It teaches that with perseverance, hard work, and humility, any dream can be achieved. It is not just a biography but a manual for life. I highly recommend it to every student who dares to dream big.

OR

(ii) Blog:

Question: Write a ‘Blog’ in a proper format on ‘Leisure and Entertainment’ with the help of the following points (100 to 150 words): Contextual meaning, Why the need?, What changes can be noticed?, Do’s and don’ts.

Recharging the Soul: The Art of Leisure

Published on July 26, 2024 | By [Student Name]

What is Leisure?
Leisure is not just free time; it is the quality of time we spend away from work and domestic chores. It is the time for recreation, entertainment, and personal growth.

Why do we need it?
In our fast-paced "hustle culture," burnout is real. Leisure acts as a reset button for the brain. It boosts creativity, reduces stress, and improves mental health.

Changing Trends:
Gone are the days when leisure meant reading a book or playing outdoors. Today, entertainment has shifted to OTT platforms, gaming, and social media scrolling. While accessible, this often leads to digital fatigue rather than relaxation.

Do's and Don'ts:
Do: Engage in active leisure like sports, hobbies, or travel. Connect with nature.
Don't: Don't let screen time consume your leisure. Don't feel guilty for taking a break.

Remember, we work to live, not live to work!

OR

(iii) Appeal:

Question: Prepare an ‘Appeal’ on the topic “Avoid Unauthorised Hoardings and Banners” with the help of the following points (100 to 150 words): Reduces the beauty of the area, Conflict, Distractions on the road, Causes accidents.

STOP THE VISUAL POLLUTION!

Say NO to Unauthorised Hoardings and Banners

Citizens of Our City,

Look around! Our beautiful city is being defaced by ugly, illegal hoardings and banners.

  • ⚠ They destroy the scenic beauty of our architecture.
  • ⚠ They cause political and social conflicts.
  • ⚠ They distract drivers, leading to fatal road accidents.
  • ⚠ They pose a danger of falling during heavy winds.

Let’s Keep Our City Clean, Green, and Safe!

Report illegal hoardings to the Municipal Corporation Helpline: 1800-XXX-XXXX

Issued in public interest by: Concerned Citizens Group

SECTION- IV: (LITERARY GENRE-NOVEL)
Q. 5. (A) Complete the activities given below as per the instructions: (4 Marks)

(i) Match the column:

Column ‘A’ Column ‘B’ (Correct Matches)
(1) Setting (c) The background of the story
(2) Conflict (d) Provides interest and curiosity
(3) Plot (a) Course of events
(4) Theme (b) Central idea

(ii) Choose the correct alternatives and rewrite the sentences:

(a) Stream of consciousness is a phrase coined by William James.

(b) Frankenstein is considered as the first novel based on science and technology.

(c) The word ‘Novella,’ is originated from the Italian word.

(d) The Picaresque novel narrates the adventures of the protagonist.

(B) Answer in about 50 words to the questions given below: (4 Marks)

(i) The extract presents E.R. Braithwaite as a silent observer in ‘To Sir, with Love.’ Explain.

Answer: In the extract concerning the half-yearly report, Braithwaite takes a back seat. He does not organize the event but allows the students to take full charge. He silently observes their presentation, their confidence, and their management skills from the audience, feeling immense pride in their transformation and independence.

(ii) Justify how the half-yearly report of Students’ Council was an important event for the teachers and students.

Answer: The event was crucial as it bridged the gap between teachers and students. For students, it was a platform to voice their opinions, demonstrate their learning, and showcase maturity. For teachers, it provided valuable feedback on their teaching methods and allowed them to see the students' development beyond just academics.

(C) Answer in about 50 words to the questions given below: (4 Marks)

(i) Compare the characters Passepartout and Detective Fix from the novel ‘Around the World in Eighty Days’.

Answer: Passepartout is loyal, emotional, and comedic, serving Fogg faithfully and aiding his journey. In contrast, Detective Fix is suspicious, calculating, and cynical. While Passepartout acts as a helper to the protagonist, Fix acts as an obstacle, constantly trying to delay Fogg to arrest him, believing him to be a bank robber.

(ii) Aouda’s acceptance of Fogg’s marriage proposal is a pleasant part in the plot of ‘Around the World in Eighty Days.’ Comment.

Answer: Fogg is depicted as a cold, mechanical man obsessed with his bet. Aouda's acceptance of his proposal signifies the humanization of Fogg. It brings a romantic and emotional climax to the story, proving that while Fogg may have thought he lost the wager (initially), he won something far more valuable—love and happiness.

(D) Answer in about 50 words to the questions given below: (4 Marks)

(i) Sherlock Holmes is the leading character in the extract ‘The Sign of Four.’ Elaborate.

Answer: Sherlock Holmes dominates the scene with his sharp intellect and deductive reasoning. He analyzes the clues (like the handwriting and pearls) with precision, providing direction to the mystery. His confident demeanor calms the client, Mary Morstan, and drives the plot forward, establishing him as the brilliant focal point of the investigation.

(ii) Narrate the case of Miss Morstan in your words.

Answer: Mary Morstan's father, an officer, disappeared ten years ago upon returning to London. For the past six years, she has received a valuable pearl annually from an unknown sender. Recently, she received a letter promising her "justice" and asking for a meeting, which led her to seek Holmes' assistance to unravel the mystery.

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