Show that the following statement pattern is contingency.
(p → q) ∧ (p → r)
SOLUTION
| p | q | r | p→q | p→r | (p→q)∧(p→r) |
| T | T | T | T | T | T |
| T | T | F | T | F | F |
| T | F | T | F | T | F |
| T | F | F | F | F | F |
| F | T | T | T | T | T |
| F | T | F | T | T | T |
| F | F | T | T | T | T |
| F | F | F | T | T | T |
The truth values in the last column are not identical. Hence, it is contingency.
