Ans. Data Given: Power = 750 W,

Time = 2 hours per day,

No. of days = 30 days.

Solution: Energy consumed = Power Rating x time of operation.

Therefore, Energy consumed = 750 W x 2 hrs x 30 days = 45000 W hour

Therefore, Energy consumed = (45000 / 1000 ) kWh.

Therefore, Energy consumed = 45 kWh.

Therefore, Energy consumed by the electric iron is 45 kWh.