Metal A has electronic configuration of 2,8,1 and metal B has 2,8,8,2 which is more reactive. Identify these metals and vie their reactions with dil HCl.


Ans. Metal A is Sodium (Na) : 2,8,1
Metal B is Calcium (Ca) : 2,8,8,2.
Metal A (Sodium) is more reactive than metal B (Calcium).

Reaction: -
i.      Sodium metal reacts violently with dilute hydrochloric acid to form sodium chlorides and hydrogen.
2Na(s) + 2HCl(aq) 2NaCl(aq) + H2(g)
ii.   Calcium reacts less vigorously to form calcium chloride and hydrogen.

Ca + 2HCl CaCl2 + H2

No comments:

Post a Comment