Points to Remember: Relation and Function | Class 10th Mathematics

Points to Remember: Relation and Function

Key Concepts

The Cartesian Product of $A$ with $B$ is defined as $A \times B = \{(a, b) \mid a \in A, b \in B\}$.
A relation R from $A$ to $B$ is always a subset of $A \times B$. That is, $R \subseteq A \times B$.
A relation R from $X$ to $Y$ is a function if for every $x \in X$ there exists only one $y \in Y$.
A function can be represented by:
- (i) an arrow diagram
- (ii) a tabular form
- (iii) a set of ordered pairs
- (iv) a graphical form
Some types of functions:
- (i) One-one function
- (ii) Onto function
- (iii) Many-one function
- (iv) Into function
Identity function: $f(x) = x$
Reciprocal function: $f(x) = \frac{1}{x}$
Constant function: $f(x) = c$
Linear function: $f(x) = ax + b, a \neq 0$
Quadratic function: $f(x) = ax^2 + bx + c, a \neq 0$
Cubic function: $f(x) = ax^3 + bx^2 + cx + d, a \neq 0$
For three non-empty sets $A$, $B$ and $C$, if $f : A \to B$ and $g : B \to C$ are two functions, then the composition of $f$ and $g$ is a function $g \circ f : A \to C$ will be defined as $(g \circ f)(x) = g(f(x))$ for all $x \in A$.
If $f$ and $g$ are any two functions, then in general, $f \circ g \neq g \circ f$.
If $f$, $g$ and $h$ are any three functions, then $f \circ (g \circ h) = (f \circ g) \circ h$.

10th Maths Unit 1 Exercise 1.4: Types of Functions Solutions

Exercise 1.4: Types of Functions - Problem Questions with Answer, Solution | Mathematics

Question 1

Determine whether the graph given below represent functions. Give reason for your answers concerning each graph.

Four graphs to be identified as functions or not.

Solution:

Question 2

Let $f : A \rightarrow B$ be a function defined by $f(x) = \frac{x}{2} - 1$, where $A = \{2, 4, 6, 10, 12\}$, $B = \{0, 1, 2, 4, 5, 9\}$. Represent $f$ by

(i) set of ordered pairs;
(ii) a table;
(iii) an arrow diagram;
(iv) a graph

Solution:

Question 3

Represent the function $f = \{(1, 2), (2, 2), (3, 2), (4, 3), (5, 4)\}$ through

(i) an arrow diagram
(ii) a table form
(iii) a graph

Solution:

Question 4

Show that the function $f: \mathbb{N} \rightarrow \mathbb{N}$ defined by $f(x) = 2x - 1$ is one-one but not onto.

Solution:

Question 5

Show that the function $f: \mathbb{N} \rightarrow \mathbb{N}$ defined by $f(m) = m^2 + m + 3$ is one-one function.

Solution:

Question 6

Let $A = \{1, 2, 3, 4\}$ and $B = \mathbb{N}$. Let $f: A \rightarrow B$ be defined by $f(x) = x^3$ then,

(i) find the range of $f$
(ii) identify the type of function

Solution:

Question 7

In each of the following cases state whether the function is bijective or not. Justify your answer.

(i) $f: \mathbb{R} \rightarrow \mathbb{R}$ defined by $f(x) = 2x + 1$
(ii) $f: \mathbb{R} \rightarrow \mathbb{R}$ defined by $f(x) = 3 - 4x^2$

Solution:

Question 8

Let $A = \{-1, 1\}$ and $B = \{0, 2\}$. If the function $f: A \rightarrow B$ defined by $f(x) = ax + b$ is an onto function? Find $a$ and $b$.

Solution:

Question 9

If the function $f$ is defined by $$ f(x) = \begin{cases} x+2 & \text{if } x > 1 \\ 2 & \text{if } -1 \le x \le 1 \\ x-1 & \text{if } -3 < x < -1 \end{cases} $$ find the values of

(i) $f(3)$
(ii) $f(0)$
(iii) $f(-1.5)$
(iv) $f(2) + f(-2)$

Solution:

Question 10

A function $f: [-5, 9] \rightarrow \mathbb{R}$ is defined as follows: $$ f(x) = \begin{cases} 6x+1 & \text{if } -5 \le x < 2 \\ 5x^2-1 & \text{if } 2 \le x < 6 \\ 3x-4 & \text{if } 6 \le x \le 9 \end{cases} $$ Find

(i) $f(-3) + f(2)$
(ii) $f(7) - f(1)$
(iii) $2f(4) + f(8)$
(iv) $\frac{2f(-2) - f(6)}{f(4) + f(-2)}$

Solution:

Question 11

The distance $S$ an object travels under the influence of gravity in time $t$ seconds is given by $S(t) = \frac{1}{2}gt^2 + at + b$ where, ($g$ is the acceleration due to gravity), $a$, $b$ are constants. Check if the function $S(t)$ is one-one.

Solution:

Question 12

The function ‘$t$’ which maps temperature in Celsius ($C$) into temperature in Fahrenheit ($F$) is defined by $t(C) = F$ where $F = \frac{9}{5}C + 32$. Find,

(i) $t(0)$
(ii) $t(28)$
(iii) $t(-10)$
(iv) the value of $C$ when $t(C) = 212$
(v) the temperature when the Celsius value is equal to the Farenheit value.

Solution:

Answers

1. (i) Not a function (ii) function (iii) Not a function (iv) function

2. (i) $\{(2,0),(4,1),(6,2),(10,4),(12,5)\}$

Image showing answers for question 2 including table, arrow diagram, and graph forms.

6. (i) $\{1, 8, 27, 64\}$ (ii) one-one and into function

7. (i) Bijective function (ii) Not bijective function

8. 1,1

9. (i) 5 (ii) 2 (iii) -2.5 (iv) 1

10. (i) 2 (ii) 10 (iii) 178 (iv) -9/17

11. Yes

12. (i) 32°F (ii) 82.4°F (iii) 14°F (iv) 100°C (v) -40°

Types of Functions: Definitions, Examples, and Solutions for 10th Grade Mathematics

Types of Functions - Definition, Illustration, Example, Solution

In this section, we will discuss the following types of functions with suitable examples.

one – one
many – one
onto
into
bijection

1. One – one function

Let us assume that we have a cell phone with proper working condition. If you make a usual call to your friend then you can make only one call at a time (Fig.1.21).

Fig 1.21: Analogy of a one-to-one function using a mobile phone call.

If we treat making calls as a function, then it will be one – one.

A function f: A→ B is called a one – one function if distinct elements of A have distinct images in B.

Equivalently, If for all a₁, a₂ ∈ A, f (a₁) = f (a₂) implies a₁ = a₂, then f is called a one – one function.

A one-one function is also called an injection.

Illustration 10

Let A = {1,2,3,4} and B = {a,b,c,d,e}.

(i) Let f = {(1,a), (2,b), (3,d), (4,c)}.

In Fig. 1.22, for different elements in A, there are different images in B. Hence f is a one – one function.

Fig 1.22: Diagram showing a one-to-one function.

(ii) Let g = {(1,a), (2,b), (3,c), (4,e)}.

g is a function from A to B such that g(1) = g(2) = b, but 1 ≠ 2.

Thus two distinct elements 1 and 2 in the first set A have same image b the second set in B (Fig.1.23). Hence, g is not a one–one function.

Fig 1.23: Diagram showing a function that is not one-to-one.

2. Many – one function

In a theatre complex three films F₁, F₂, F₃ are shown. Seven persons (P₁ to P₇) arrive at the theatre and buy tickets as shown (Fig 1.24).

Fig 1.24: Analogy of a many-to-one function with people choosing movies.

If the selection of films is considered as a relation, then this is a function which is many–one, since more than one person may choose to watch the same film.

A function f: A→ B is called a many-one function if two or more elements of A have same image in B.

In other words, a function f: A→ B is called many-one if f it is not one–one.

Illustration 11

Let A = {1,2,3,4} and ; Let f = {(1,a), (2,a), (3,b), (4,c)}.

Then f is a function from A to B in which different elements 1 and 2 of A have the same image a in B. Hence f is a many – one function.

3. Onto function

In a mobile phone assume that there are 3 persons in the contact. If every person in the contact receives a call, then the function representing making calls will be onto. (Fig.1.25)

Fig 1.25: Analogy of an onto function where every contact receives a call.

A function f: A→ B is said to be an onto function if the range of f is equal to the co-domain of f.

In other words, every element in the co-domain B has a pre-image in the domain A. An onto function is also called a surjection.

Note: If f : A → B is an onto function then, the range of f = B . That is, f(A) = B .

Illustration 12

Let A = {x,y, z}, B = {l,m,n} ; Range of f = {l,m,n} = B (Fig.1.26)

Fig 1.26: Diagram illustrating an onto function.

Hence f is an onto function.

4. Into function

In a home appliance showroom, the products television, air conditioner, washing machine and water heater were provided with 20% discount as new year sale offer. If the selection of the above products by the three customers C₁, C₂, C₃ is considered as a function then the following diagram (Fig.1.27) will represent an into function.

Fig 1.27: Analogy of an into function where not all appliances are chosen by customers.

During winter season customers usually do not prefer buying air conditioner. Here air conditioner is not chosen by any customer. This is an example of into function.

A function f: A→ B is called an into function if there exists atleast one element in B which is not the image of any element of A.

That is the range of f is a proper subset of the co-domain of f.

In other words, a function f: A→ B is called ‘into’ if it is not ‘onto’.

Illustration 13

Let A = {1,2,3} and B = {w, x,y, z}; f = {(1,w),(2, z),(3,x)}.

Here, range of f = {w, x, z} ⊂ B (Fig.1.28)

Fig 1.28: Diagram illustrating an into function.

Therefore, f is a into function. Note that y ∈ B is not an image of any element in A.

5. Bijection

Consider the circle where each letter of the English alphabet is changed from inner portion to a letter in the outer portion.

Fig 1.29: Bijection Cipher Circle for cryptography example.

Thus A→ D, B→ E, C → F, … Z→ C. We call this circle as ‘cipher circle’. (Fig.1.29) In this way if we try to change the word ‘HELLO’ then it will become ‘KHOOR’. Now using the same circle if we substitute for each outer letter the corresponding inner letter we will get back the word ‘HELLO’. This process of converting from one form to an other form and receiving back the required information is called bijection. This process is widely used in the study of secret codes called ‘cryptography’.

If a function f : A→ B is both one–one and onto, then f is called a bijection from A to B.

Illustration 14

This image illustrates that a function which is one-one and onto is called a bijection.

Illustration that One-one + Onto = Bijection.

Note: A one – one and onto function is also called a one – one correspondence.

6. Horizontal Line Test

Previously we have seen the vertical line test. Now let us see the horizontal line test. “A function represented in a graph is one–one, if every horizontal line intersects the curve in at most one point”.

Example 1.12

Using horizontal line test (Fig.1.35(a), 1.35(b), 1.35(c)), determine which of the following functions are one – one.

Fig 1.35: Three graphs demonstrating the horizontal line test.

Solution

The curves in Fig.1.35(a) and Fig.1.35(c) represent a one–one function as the horizontal lines meet the curves in only one point P.

The curve in Fig.1.35(b) does not represent a one–one function, since, the horizontal line meets the curve in two points P and Q.

Example 1.13

Let A = {1, 2, 3}, B = {4, 5, 6, 7} and f = {(1, 4),(2, 5),(3, 6)} be a function from A to B. Show that f is one – one but not onto function.

Solution

A = {1, 2, 3}, B = {4, 5, 6, 7} ; f = {(1, 4),(2, 5),(3, 6)}.

Fig 1.36: Diagram showing a one-one but not onto function.

Then f is a function from A to B and for different elements in A, there are different images in B. Hence f is one–one function. Note that the element 7 in the co-domain does not have any pre-image in the domain. Hence f is not onto (Fig.1.36).

Therefore f is one–one but not an onto function.

Example 1.14

If A = {−2,−1, 0,1, 2} and f: A→ B is an onto function defined by f(x) = x² + x + 1 then find B.

Solution

Given A = {−2,−1, 0,1, 2} and f(x) = x² + x + 1.

f(-2) = (−2)² + (−2) + 1 = 3;

f(-1) = (−1)² + (−1) + 1 = 1;

f(0) = 0² + 0 + 1 = 1;

f(1) = 1² + 1 + 1 = 3;

f(2) = 2² + 2 + 1 = 7;

Since, f is an onto function, range of f = B = co-domain of f.

Therefore, B = {1, 3, 7}.

Example 1.15

Let f be a function f: N → N be defined by f(x) = 3x + 2, x ∈ N.

(i) Find the images of 1, 2, 3

(ii) Find the pre-images of 29, 53

(iii) Identify the type of function

Solution

The function f: N → N is defined by f(x) = 3x + 2.

(i) If x = 1, f(1) = 3(1) + 2 = 5

If x = 2, f(2) = 3(2) + 2 = 8

If x = 3, f(3) = 3(3) + 2 = 11

The images of 1, 2, 3 are 5, 8, 11 respectively.

(ii) If x is the pre-image of 29, then f(x) = 29. Hence 3x + 2 = 29. 3x = 27 ⇒ x = 9.

Similarly, if x is the pre-image of 53, then f(x) = 53. Hence 3x + 2 = 53. 3x = 51 ⇒ x = 17.

Thus the pre-images of 29 and 53 are 9 and 17 respectively.

(iii) Since different elements of N have different images in the co-domain, the function f is one – one function. The co-domain of f is N. But the range of f = {5, 8, 11, 14, 17, ...} is a proper subset of N. Therefore f is not an onto function. That is, f is an into function. Thus f is one – one and into function.

Example 1.16

Forensic scientists can determine the height (in cms) of a person based on the length of their thigh bone. They usually do so using the function h(b) = 2.47b + 54.10 where b is the length of the thigh bone.

(i) Check if the function h is one – one

(ii) Also find the height of a person if the length of his thigh bone is 50 cms.

(iii) Find the length of the thigh bone if the height of a person is 147.96 cms.

Solution

(i) To check if h is one – one, we assume that h(b₁) = h(b₂). Then we get, 2.47b₁ + 54.10 = 2.47b₂ + 54.10. 2.47b₁ = 2.47b₂ ⇒ b₁ = b₂. Thus, h(b₁) = h(b₂) ⇒ b₁ = b₂. So, the function h is one – one.

(ii) If the length of the thigh bone b = 50, then the height is h(50) = (2.47 × 50) + 54.10 = 177.6 cms.

(iii) If the height of a person is 147.96 cms, then h(b) = 147.96 and so the length of the thigh bone is given by 2.47b + 54.10 = 147.96. b = [ 93.86 / 2.47 ] = 38. Therefore, the length of the thigh bone is 38 cms.

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