Probability, Problem Set No 5, SSC New Syllabus, Maths I, Maharashtra
Step 1: Determine the Sample Space (S)
When a standard six-sided die is thrown, the possible outcomes are numbers from 1 to 6.
\[ S = \{1, 2, 3, 4, 5, 6\} \]
Therefore, the total number of possible outcomes is:
\[ n(S) = 6 \]
Step 2: Define Event A
Let \( A \) be the event of getting an odd number.
The odd numbers on a die are 1, 3, and 5.
\[ A = \{1, 3, 5\} \]
Therefore, the number of favorable outcomes is:
\[ n(A) = 3 \]
Step 3: Calculate Probability
The probability of an event is given by the formula: \[ P(A) = \frac{n(A)}{n(S)} \]
Substituting the values: \[ P(A) = \frac{3}{6} \]
Simplifying the fraction: \[ P(A) = \frac{1}{2} \]
| Sr. No. | Random Experiments | Sample Space | No. of sample points |
| 1 | A coin is tossed | S = {H,T} | n(S) = 2 |
| 2 | Two coins are tossed | S = {HH, HT, TH, TT} | n(S) = 4 |
| 3 | Three coins are tossed | S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT | n(S) = 8 |
| 4 | A die is thrown | S = {1,2,3,4,5,6} | n(S) = 6 |
| 5 | A card is drawn from a pack containing 25 cards | S = {1,2,3, ... ,25} | n(S) = 25 |
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