Showing posts with label 27. Show all posts
Showing posts with label 27. Show all posts

Find the next four terms. 3, 9, 27, 81, ..... (1 mark)

Geometric Sequence Problem

Geometric Sequence Problem & Solution

(ii) Determine the next four terms of the sequence: \(3, 9, 27, 81, \dots\) (1 mark)

Solution:

Let the terms of the sequence be denoted by \(t_n\).

\(t_1 = 3^1 = 3\)

\(t_2 = 3^2 = 9\)

\(t_3 = 3^3 = 27\)

\(t_4 = 3^4 = 81\)

The general term of this geometric sequence is \(t_n = 3^n\). We need to find the next four terms, which are \(t_5, t_6, t_7, \text{ and } t_8\).

\(t_5 = 3^5 = 243\)

\(t_6 = 3^6 = 729\)

\(t_7 = 3^7 = 2187\)

\(t_8 = 3^8 = 6561\)

\(\therefore\) The next four terms of the sequence are 243, 729, 2187, and 6561.