3y2 + 9y + 4 = 0

(v) 3y² + 9y + 4 = 0

Sol. 3y² + 9y + 4 = 0

Comparing with ay² + by + c = 0 we have a = 3, b = 9, c = 4

∆  = b² – 4ac

= (9)² – 4 (3) (4)

= 81 – 48

= 33

∴ ∆  > 0

Hence roots of the quadratic equation are real and unequal.