15)A Relation R is given by the set \(\{(x,y) / y = x + 3, x \in \{0, 1, 2, 3, 4, 5\}\}\). Determine its domain and range.

10th Standard Maths Quarterly Exam Sep 2024 Answer Key | Brindhavan HR SEC School

15)A Relation R is given by the set \(\{(x,y) / y = x + 3, x \in \{0, 1, 2, 3, 4, 5\}\}\). Determine its domain and range.

Answer: Given Set = \(\{(x,y) / y = x + 3, x \in \{0, 1, 2, 3, 4, 5\}\}\)

When x = 0, y = 0 + 3 = 3

When x = 1, y = 1 + 3 = 4

When x = 2, y = 2 + 3 = 5

When x = 3, y = 3 + 3 = 6

When x = 4, y = 4 + 3 = 7

When x = 5, y = 5 + 3 = 8

Relation R = \(\{(0, 3), (1,4), (2,5), (3,6), (4,7), (5,8)\}\)

Domain of R = {0, 1, 2, 3, 4, 5}

Range of R = {3, 4, 5, 6, 7, 8}