Question 19.

Solve the example.

An electric iron of 1100 W is operated for 2 hrs daily. What will be the electrical consumption expenses for that in the month of April? (The electric company charges Rs 5 per unit of energy).

Answer:

Power of electric iron = 1100 W

Time t = 2 hrs

So energy consumed daily = P x t

= 1100 x 2

= 2200 Wh

For 30 days since the month of April has 30 days

Energy consumed= 2200 x 30

= 66000 Wh

= 66 Kwh

1 Kwh = 1 unit = Rs 5

So 6.6 Kwh = 5 x 66 = 330 rupees

So the bill for month of April will be 330 rupees.