Mastering Quadratic Equations
What you will learn
A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is \( ax^2 + bx + c = 0 \). Below are 25 fully solved examples to help you understand factorization and formula methods, followed by 10 practice problems to test your skills.
Note: Try to solve the equation yourself first, then click "Show Solution" to verify your method.
25 Solved Examples
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(ii) Factorize The numbers are 2 and 3. \[ x^2 + 2x + 3x + 6 = 0 \] \[ x(x + 2) + 3(x + 2) = 0 \] \[ (x + 2)(x + 3) = 0 \]
(iii) Find Roots Either \(x+2=0\) or \(x+3=0\).
Answer: \( x = -2, x = -3 \)
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(ii) Split the middle term \[ x^2 - 2x - 3x + 6 = 0 \] \[ x(x - 2) - 3(x - 2) = 0 \] \[ (x - 2)(x - 3) = 0 \]
(iii) Solve Answer: \( x = 2, x = 3 \)
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(ii) Factorize \[ x^2 - 3^2 = 0 \] \[ (x + 3)(x - 3) = 0 \]
(iii) Solve Answer: \( x = -3, x = 3 \)
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(ii) Factorize \[ (x + 3)(x + 4) = 0 \]
(iii) Solve Answer: \( x = -3, x = -4 \)
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(ii) Split middle term \[ 2x^2 + 2x + x + 1 = 0 \] \[ 2x(x + 1) + 1(x + 1) = 0 \] \[ (2x + 1)(x + 1) = 0 \]
(iii) Solve \( 2x = -1 \rightarrow x = -1/2 \) or \( x = -1 \).
Answer: \( x = -\frac{1}{2}, x = -1 \)
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(ii) Factorize \[ (x - 5)(x + 3) = 0 \]
(iii) Solve Answer: \( x = 5, x = -3 \)
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(ii) Factorize \[ (x - 4)^2 = 0 \]
(iii) Solve Answer: \( x = 4 \) (Equal real roots)
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(ii) Split middle term \[ 3x^2 - 3x - 2x + 2 = 0 \] \[ 3x(x - 1) - 2(x - 1) = 0 \] \[ (3x - 2)(x - 1) = 0 \]
(iii) Solve Answer: \( x = \frac{2}{3}, x = 1 \)
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(ii) Factorize \[ x(x + 4) = 0 \]
(iii) Solve Answer: \( x = 0, x = -4 \)
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(ii) Split middle term \[ 2x^2 - 6x - x + 3 = 0 \] \[ 2x(x - 3) - 1(x - 3) = 0 \] \[ (2x - 1)(x - 3) = 0 \]
(iii) Solve Answer: \( x = \frac{1}{2}, x = 3 \)
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(ii) Factorize \[ (x - 7)(x + 3) = 0 \]
(iii) Solve Answer: \( x = 7, x = -3 \)
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(ii) Substitute \[ x = \frac{-4 \pm \sqrt{16 - 8}}{2} \] \[ x = \frac{-4 \pm \sqrt{8}}{2} \] \[ x = \frac{-4 \pm 2\sqrt{2}}{2} \]
(iii) Simplify Answer: \( x = -2 \pm \sqrt{2} \)
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(ii) Split middle term \[ 6x^2 - 4x + 3x - 2 = 0 \] \[ 2x(3x - 2) + 1(3x - 2) = 0 \] \[ (2x + 1)(3x - 2) = 0 \]
(iii) Solve Answer: \( x = -\frac{1}{2}, x = \frac{2}{3} \)
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(ii) Factorize \[ (2x - 3)^2 = 0 \]
(iii) Solve Answer: \( x = \frac{3}{2} \) (Repeated root)
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(ii) Factorize \[ (x + 2)(x - 1) = 0 \]
(iii) Solve Answer: \( x = -2, x = 1 \)
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(ii) Square root \( x = \pm\sqrt{4} \).
(iii) Solve Answer: \( x = 2, x = -2 \)
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(ii) Factorize \[ (x - 8)(x - 3) = 0 \]
(iii) Solve Answer: \( x = 8, x = 3 \)
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(ii) Factorize \[ (x + 5)^2 = 0 \]
(iii) Solve Answer: \( x = -5 \)
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(ii) Split middle term \[ 2x^2 + 6x - x - 3 = 0 \] \[ 2x(x + 3) - 1(x + 3) = 0 \] \[ (2x - 1)(x + 3) = 0 \]
(iii) Solve Answer: \( x = \frac{1}{2}, x = -3 \)
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(ii) Calculate \[ x = \frac{6 \pm \sqrt{36 - 28}}{2} \] \[ x = \frac{6 \pm \sqrt{8}}{2} \] \[ x = \frac{6 \pm 2\sqrt{2}}{2} \]
(iii) Simplify Answer: \( x = 3 \pm \sqrt{2} \)
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(ii) Factorize \[ (x + 5)(x - 2) = 0 \]
(iii) Solve Answer: \( x = -5, x = 2 \)
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(ii) Factorize common term \[ x(3x - 2) = 0 \]
(iii) Solve \( x = 0 \) or \( 3x - 2 = 0 \).
Answer: \( x = 0, x = \frac{2}{3} \)
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(ii) Factorize \[ (x - 6)(x - 7) = 0 \]
(iii) Solve Answer: \( x = 6, x = 7 \)
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(ii) Factorize \[ (2x - 1)(2x + 1) = 0 \]
(iii) Solve Answer: \( x = \frac{1}{2}, x = -\frac{1}{2} \)
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(ii) Factorize \[ (x + 3)(x + 5) = 0 \]
(iii) Solve Answer: \( x = -3, x = -5 \)
Practice Questions
Try solving these 10 questions on your own before checking the answer key below.
(i) \( x^2 + 7x + 10 = 0 \)
(ii) \( x^2 - 3x - 10 = 0 \)
(iii) \( 2x^2 + 5x + 3 = 0 \)
(iv) \( x^2 - 49 = 0 \)
(v) \( x^2 - 6x = 0 \)
(vi) \( x^2 + 12x + 36 = 0 \)
(vii) \( 3x^2 - x - 4 = 0 \)
(viii) \( x^2 - x - 30 = 0 \)
(ix) \( x^2 - 10x + 21 = 0 \)
(x) \( 2x^2 + 7x - 4 = 0 \)
Check Answer Key
(i) \( x = -2, x = -5 \)
(ii) \( x = 5, x = -2 \)
(iii) \( x = -1, x = -3/2 \)
(iv) \( x = 7, x = -7 \)
(v) \( x = 0, x = 6 \)
(vi) \( x = -6 \)
(vii) \( x = -1, x = 4/3 \)
(viii) \( x = 6, x = -5 \)
(ix) \( x = 3, x = 7 \)
(x) \( x = 1/2, x = -4 \)