x + 4y = 14000

x + 2y = 11000

() ()
()

2y = 3000

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7. A man starts his job with a certain monthly salary and a fixed increment every year. If his salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service. What is his starting salary and what is the annual increment ?
Solution. Let
starting salary of man be Rs. x and the fixed annual increment be Rs. y.
As per the first given condition,
x + 2y = 11000 ......(1)
As per the second given
condition,
x + 4y = 14000 ......(2)
Subtracting (1) from (2),
∴ y = 3000/2
∴ y = 1500
Substituting y = 1500 in equation
(1)
x + 2y = 11000
∴ x + 2(1500) =
11000
∴ x + 3000 =
11000
∴ x = 11000 –
3000
∴ x = 8000
∴ The starting salary of man is Rs. 8000
and his fixed annual increment is Rs. 1500.