y2 + 6y – 2 = 0

(ii) y² + 6y – 2 = 0

Sol. y² + 6y – 2 = 0

Comparing with ay² + by + c = 0 we have a = 1, b = 6, c = – 2

∆  = b² – 4ac

= (6)² – 4 (1) (– 2)

= 36 + 8

= 44

∆  > 0

Hence roots of the quadratic equation are real and unequal.