2. The taxi fare is Rs. 14 for the first kilometer and Rs. 2 for each additional kilometer. What will be fare for 10 kilometers ?
Sol. Since the taxi fare increases by Rs. 2 every kilometer after the first, the successive taxi fares form an A.P.
The taxi fare for first kilometer (a) = Rs. 14
Increase in taxi fare in every kilometer after first kilometer (d) = 2
No. of kilometers covered by taxi (n) = 10
Taxi fare for 10 kilometers = t10 = ?
tn = a + (n + 1) d
∴ t10 = a + (10 – 1) d
∴ t10 = 14 + 9 (2)
∴ t10 = 14 + 18
∴ t10 = 32