(iii) tn = n + 2 (1 mark)

(iii) t_n = n + 2 (1 mark)

Sol. t_n = n + 2

∴  t₁ = 1 + 2 = 3

∴  t₂ = 2 + 2 = 4

∴ t₃ = 3 + 2 = 5

∴ t₄ = 4 + 2 = 6

∴ t₅ = 5 + 2 = 7

∴ The first five terms of the sequence are 3, 4, 5, 6 and 7.