(iii) 1, 3, 7, 15, 31, .... (1 mark)


(iii) 1, 3, 7, 15, 31, .... (1 mark)

Sol. t1 = 1
t2 = t1 + 2 = 1+ 2 = 3
t3 = t2 + 4 = 3 + 4 = 7
t4 = t3 + 8 = 7 + 8 = 15
t5 = t4 + 16  = 15 + 16 = 31
t6 = t5 + 32  = 31 + 32 = 63
t7 = t6  + 64  = 63 + 64 = 127
t8 = t7  + 128  = 127 + 128 = 255
t9 = t8  + 256  = 255 + 256 = 511

The next four terms of the sequence are 63, 127, 255 and 511.

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