Solution

t_{n} = 3n +
1 [Given]

∴ t_{1} = 3(1)
+ 1 = 3 + 1 = 4

∴ t_{2} = 3(2) + 1 = 6 + 1 = 7

∴ t_{3} = 3(3) + 1 = 9 + 1 = 10

∴ t_{4} = 3(4) + 1 = 12 + 1 = 13


∴ The first four terms of the given sequence is 4, 7, 10 and 13.
