2y2 + 5y – 3 = 0


(iv) 2y2 + 5y – 3 = 0

Sol. 2y2 + 5y – 3 = 0
Comparing with ay2 + by + c = 0 we have a = 2, b = 5, c = – 3
∆ = b2 – 4ac
= (5)2 – 4 (2) (– 3)
= 25 + 24
= 49
∴ ∆  > 0

Hence roots of the quadratic equation are real and unequal.