Solution:
Comparing the given equation 2y^{2} + 5 y – 3 = 0 with the standard
quadratic equation ax^{2} + bx + c = 0 we get,

a
= 2, b = 5 and c =  3

Discriminant
∆ = b^{2} – 4ac

∴ ∆ = 5^{2} – 4
(2) (3)

∴ ∆ = 25 + 24

∴ ∆ = 49


∵ ∆ > 0

∴ the nature of the root is real and
unequal.
