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»
In the adjoining figure
»
pint Q is on the side MP such that MQ = 2 and MP = 5.5. Ray NQ is the bisector of ∠ MNP of ∆ MNP. Find MN:NP.
»
In the adjoining figure, pint Q is on the side MP such that MQ = 2 and MP = 5.5. Ray NQ is the bisector of ∠ MNP of ∆ MNP. Find MN:NP.
In the adjoining figure, pint Q is on the side MP such that MQ = 2 and MP = 5.5. Ray NQ is the bisector of ∠ MNP of ∆ MNP. Find MN:NP.
Solution :
M, Q and P are collinear points
∴
MP = MQ + QP [
∵
M – Q – P ]
∴
5.5 = 2 + QP
∴
5.5 – 2 = QP
∴
QP = 3.5
In ∆MNP , Ray NQ is the bisector of
∠
MNP of ∆ MNP,
MN
=
MQ
[By Angle bisector theorem]
NP
QP
MN
=
2
NP
3.5
MN
=
2
×
10
NP
3.5
×
10
MN
=
20
NP
35
MN
=
4
NP
7
∴
MN : NP = 4: 7
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