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Similarity Extra HOTS for Practice with solution

In ∆ PQR, AB || QR. If AB is 3 cm, PB is 2 cm and PR is 6 cm, then find the length of of QR.

 

D is the midpoint of the side BC of ∆ ABC. If P and Q are points on AB and on AC such that DP bisects ∠BDA and DQ bisects ∠ADC, then prove that PQ || BC.

 

In ∆ ABC, AE is the external bisector of ∠A, meeting BC produced at E. If AB = 10 cm, AC = 6 cm and BC = 12 cm, then find CE.

 

In ∆ ABC, the internal bisector AD of ∠ A meets the side BC at D. If BD = 2.5cm, AB = 5 cm and AC = 4.2 cm, then find DC.

 

In triangle ABC, points D, E and F are taken on the sides AB, BC and CA respectively such that DE || AC and FE || AB.

 

In triangle PQR, given that S is a point on PQ such that ST is parallel to QR and PA:SQ = 3:5, If PR = 5.6 cm, then find PT.

 

In Triangle ABC. DE is parallel to BC and AD:DB = 2:3, IF AE = 3.7 cm, Find EC.


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Labels: Similarity Extra HOTS for Practice with solution
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 Maharashtra 

XII (12) HSC

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X (10) SSC

9th (Maharashtra)

5th (Maharashtra)

6th (Maharashtra)

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Tamil Nadu 

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11th Std.

10th Std

9th Std.

8th Std.

7th Std.

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TNPSC

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Exam Resources 

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Leaflet Writing

Report Writing

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Interview Writing

View & Counterview

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