|
Here, a = 3, d = 6 – 3
= 3
|
|
We know that,
|
|
tn = a + (n
– 1) d
|
|
∴ tn = 3 + (n – 1) 3
|
|
∴ tn = 3 + 3n – 3
|
|
∴ tn = 3n
|
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