Find Dx and Dy of the given simultaneous equations. 3x – 2y = 3 and 2x + y = 16.

Solution:

Let 3x  - 2y  = 3 ------------------eq. no. (1)

2x + y = 16 -----------------------eq. no. (2)

∴ D = 3 -2 2 1 ∴ D = 3 + 4 = 7

∴ Dx = 3 -2 16 1 ∴ Dx = 3 + 32 = 35

Dy = 3 3 2 16 ∴ Dy = 48 – 6 = 42

Now we have, D = 7 , Dx = 35 and Dy  = 42

∴ By Cramer's Rule

x = Dx/D = 35/7 = 5

y = Dy / D = 42 / 7 = 6