Exercise 1.6 | Q 5.2 | Page 16
Show that the following statement pattern is contingency.
(p → q) ↔ (~ p ∨ q)
p | q | ~p | p→q | ~p∨q | (p→q)↔(~p∨q) |
T | T | F | T | T | T |
T | F | F | F | F | T |
F | T | T | T | T | T |
F | F | T | T | T | T |
All the truth values in the last column are T. Hence, it is a tautology. Not contingency.
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