6. A kite is flying at a height of 60 m
above the ground. The string attached to the kite is temporarily tied to the
ground. The inclination of the string
with the ground is 60º. Find the length if the string, assuming that there is no slack
in the string. ( √3 = 1.73)
Sol.
seg AB represents the distance of a kite
from ground.
∴ AB = 60 m
seg AC represents the length of the
string
m ∠ ACB = 60º
In right angled ∆ ABC,
sin 600 = side opposite to 600
/Hypotenuse
∴ sin 600 = AB/AC
∴ √3/2 = 60/AC
∴ AC = 120/√3
∴ AC = (120/√3)× (√3/√3)
∴ AC = 40√3 m
∴ AC = 40 × 1.73
∴ AC
= 69.2 m
∴ The
length of the string, assuming that there is no slack in the string is 69.2 m.